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seraphim [82]
3 years ago
10

A right rectangle prism has a length of 5 cm a width of 4 cm and a height of 3 cm the dimensions of the prism are doubled what i

s the surface area of the larger prism
Mathematics
1 answer:
IRISSAK [1]3 years ago
5 0

Answer: 376 cm^2

Step-by-step explanation:

First you would double all the dimensions:

l = 5 cm x 2 = 10 cm

w = 4 cm x 2 = 8 cm

h = 3 cm x 2 = 6 cm

The formula for finding the surface area of a rectangular prism is A=2(wl+hl+hw)

Substitute the values:

A=2(8*10+6*10+6*8)

Solve using PEMDAS:

A=2(80+60+48)

A=2(188)

A=376

Surface area is always in units^2:

376 cm^2

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ANSWER

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EXPLANATION

The law of cosine is given by the formula:

{b}^{2} = {a}^{2} + {c}^{2} - 2bc \cos(B)

From the diagram,

a=17, b=8, c=16

We substitute the given values into the formula to obtain:

{8}^{2} = {17}^{2} + {16}^{2} - 2(17)(16)\cos(B)

64 = 289+ 256- 544\cos(B)


64 = 545- 544\cos(B)


64 - 545 = - 544\cos(B)

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