Answer:
option b is the answer of your question
Final result :
9y - 17z - 2
Step by step solution :
Step 1 :
1
Simplify —
3
Equation at the end of step 1 :
1
— • (27y - 51z - 6)
3
Step 2 :
Pulling out like terms :
3.1 Pull out like factors :
27y - 51z - 6 = 3 • (9y - 17z - 2)
Final result :
9y - 17z - 2
Answer:
P=41.72
Step-by-step explanation:
S=ACxDB/2
81.7=8.6xDB/2
81.7=4.3xDB|:4.3
19(mm)=DB
DO=19/2=9.5
OC=8.6/2=4.3
(O is the center of the rhombus, where two diagonals meet)
a²+b²=c² (DO²+OC²=DC²)
9.5²+4.3²=c²
90.25+18,49=c²
√108,74=√c²
c≈10.43
P=4c
P=4x10.43
P=41.72
Hope it helps:)
Answer: 
Step-by-step explanation:
The given radical expressions are:


Let
= amount of salt (in pounds) in the tank at time
(in minutes). Then
.
Salt flows in at a rate

and flows out at a rate

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.
Then the net rate of salt flow is given by the differential equation

which I'll solve with the integrating factor method.



Integrate both sides. By the fundamental theorem of calculus,





After 1 hour = 60 minutes, the tank will contain

pounds of salt.