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3 years ago

Question 8. I need help with

Mathematics

1 answer:

ziro4ka [17]3 years ago

4 0

Answer:B is the right answer. Everything is divisible by 2x so divide 2x by all three components and leave remaining components letters in parentheses)

Step-by-step explanation:

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2. Suppose that

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Answer:

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3 years ago

Find the sum of the three expressions and choose the correct answer. 2x 2 y 2 - 7xy + 5y 2 8xy - 3y 2 x 2 y 2 + 4y 2

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2x^2y^2 - 7xy + 5y^2 + 8xy - 3y^2 + x^2y^2 + 4y^2

3x^2y^2 - 7xy + 5y^2 + 8xy -3y^2 + 4y^2

3x^2y^2 + xy + 5y^2 - 3y^2 + 4y^2

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3 years ago

Ax+by=(a-b) , bx - ay =(a+b) simultaneous linear equations using cross multiplication

Molodets [167]

Answer:

$x=1\,,\,y=-1$

Step-by-step explanation:

Given: $ax+by=a-b\,,\,bx-ay=a+b$

To solve: the given linear equations

Solution:

Consider the equations:

$A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0$

By method of cross multiplication:

$\frac{x}{B_1C_2-B_2C_1}=\frac{y}{C_1A_2-C_2A_1}=\frac{1}{A_1B_2-A_2B_1}$

For equations: $ax+by=a-b\,,\,bx-ay=a+b$

$ax+by-(a-b)=0\\bx-ay-(a+b)=0$

Take $A_1=a\,,\,B_1=b\,,\,C_1=-(a-b)\,,\,A_2=b\,,\,B_2=-a\,,\,C_2=-(a+b)$

So,

$\frac{x}{-b(a+b)-a(a-b)}=\frac{y}{-b(a-b)+a(a+b)}=\frac{1}{-a^2-b^2}\\\frac{x}{-ab-b^2-a^2+ab}=\frac{y}{-ab+b^2+a^2+ab}=\frac{1}{-(a^2+b^2)}\\\frac{x}{-(a^2+b^2)}=\frac{y}{a^2+b^2}=\frac{1}{-(a^2+b^2)}\\\frac{x}{-(a^2+b^2)}=\frac{1}{-(a^2+b^2)}\,,\,\frac{y}{a^2+b^2}=\frac{1}{-(a^2+b^2)}\\x=1\,,\,y=-1$

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3 years ago

What is the difference of 11 and 3.5?

Deffense [45]

7.5

Explanation:
11-3.5=
Take 3 away form 11 and then get 8 then subtract.5 and you are left with 7.5

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