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zlopas [31]
3 years ago
10

Reduce fraction: a^3+a^2b/5a times 25/3b+3a

Mathematics
1 answer:
Margaret [11]3 years ago
3 0

ANSWER

\frac{5a}{3}

EXPLANATION

The given fractions are:

\frac{{a}^{3}  +  {a}^{2} b}{5a}  \times  \frac{25}{3b + 3a}

We factor to obtain:

\frac{{a}^{2}(a  +   b)}{5a}  \times  \frac{25}{3(a + b)}

We cancel the common factors to get:

\frac{{a}(1)}{1}  \times  \frac{5}{3(1)}

We multiply the numerators and also multiply the denominators to get:

\frac{5a}{3}

Therefore the two fractions simplifies to \frac{5a}{3}

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Answer:

a)=251.2 cm    b)=50240 cm

Step-by-step explanation:

a) The formula for calculating the circumference of a circle is c=d*pie, where D is the diameter of the circle.

Therefore, C = 2 * 40 * 3.14 = 251.2 cm

b) The distance covered by 200 revolutions of the wheel is 200 times the circumference, 200*251.2=50240 cm.So to think about this we can assume that there is a point A on the wheel, the distance that point A travels when it rotates 200 times.

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2 years ago
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0.3188646

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