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zlopas [31]
3 years ago
10

Reduce fraction: a^3+a^2b/5a times 25/3b+3a

Mathematics
1 answer:
Margaret [11]3 years ago
3 0

ANSWER

\frac{5a}{3}

EXPLANATION

The given fractions are:

\frac{{a}^{3}  +  {a}^{2} b}{5a}  \times  \frac{25}{3b + 3a}

We factor to obtain:

\frac{{a}^{2}(a  +   b)}{5a}  \times  \frac{25}{3(a + b)}

We cancel the common factors to get:

\frac{{a}(1)}{1}  \times  \frac{5}{3(1)}

We multiply the numerators and also multiply the denominators to get:

\frac{5a}{3}

Therefore the two fractions simplifies to \frac{5a}{3}

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Step 2

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<u>Find the cosine of the angle BAD</u>

we know that

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we know that

cos(BAC)=cos (BAD)=\frac{5}{13}

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AC=(13*13)/5=33.8\ units

Step 4

<u>Find the length of the segment DC</u>

we know that

DC=AC-AD

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AC=33.8\ units

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substitute the values

DC=33.8\ units-5\ units

DC=28.8\ units

Step 5

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Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

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substitute the values

BC^{2}=12^{2}+28.8^{2}

BC^{2}=973.44

BC=31.2\ units

therefore

<u>the answer is</u>

BC=31.2\ units

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