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Evgen [1.6K]
3 years ago
11

The area of a rectangle is 162/3 ft2 . The length is 61/4 . Find the width. Show all work

Mathematics
1 answer:
brilliants [131]3 years ago
3 0

Answer:

I have gotten 216/61, but I am not sure if this is right.

Step-by-step explanation:

By using the "Keep It, Change It, Flip It" tactic, I was able to come up with an answer and simplify it.

1. Keep the original divisor.

    162/3

2. Change the sign.

    Division becomes multiplication.

3. The last fraction is reciprocated.

    61/4 becomes 4/61.

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Division is repeated subtraction, just like multiplication is repeated addition. If you divide 50 by 10, you get 5. This is also the question: How many times do you have to subtract 10 from 50 to get 0?
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For a circle with a radius of 15 cm, what is the length of an arc intercepted by an angle measuring 120°?
slega [8]

Answer: 31.43 cm

Step-by-step explanation:

The length of an arc  is calculated using the formula:

\frac{theta}{360} X 2\pir

where : theta is the angle in degree

r = radius

If the angle is given in Radian , the length can be calculated using the formula:

L = r∅

Since , the angle is given in degree , we will use the first formula.

L = \frac{theta}{360} X 2\pir

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3 years ago
Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

  • There are 100 students
  • 65 are members of a mathematics club
  • 40 are members of a physics club
  • 10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

  club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

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∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

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∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

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∵ 15 of them are members of the physics club

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c. 25 students only are members of the physics club

Learn more:

You can learn more about word problems in brainly.com/question/8907574

#LearnwithBrainly

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