Complete Question
The complete question is shown on the first uploaded image
Answer:
The derivative is
The correct option is option 1
Explanation:
From the question we are told that
The equation of the speed of the wave of invasion is ![v(r) = 2 \sqrt{Dr}](https://tex.z-dn.net/?f=v%28r%29%20%20%3D%202%20%5Csqrt%7BDr%7D)
=> ![v(r) = 2 (Dr)^{\frac{1}{2} }](https://tex.z-dn.net/?f=v%28r%29%20%20%3D%202%20%28Dr%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D)
=> ![v(r) = 2 * D^{\frac{1}{2} } r^{\frac{1}{2} }](https://tex.z-dn.net/?f=v%28r%29%20%20%3D%202%20%2A%20D%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%20r%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D)
Here r is the reproductive rate and the D is the parameter qualifying dispersal
Generally the derivative of this speed is mathematically represented as
![v(r)' = \frac{2}{2} * D^{\frac{1}{2} } * r^{-\frac{1}{2} }](https://tex.z-dn.net/?f=v%28r%29%27%20%3D%20%5Cfrac%7B2%7D%7B2%7D%20%20%2A%20%20D%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%20%2A%20%20r%5E%7B-%5Cfrac%7B1%7D%7B2%7D%20%7D)
=>
This derivative of the speed represents the rate of change of the invasive speed with respect to the the reproductive rate of an individual
<span> static friction :) your very welcome
</span>
Answer:
v = 15.23 m/s
Explanation:
Given that,
Mass of a car, m = 1110 kg
Initial velocity, u = 21 m/s
Force,F = -8000 N
Time, t = 0.9 s
We need to find the final velocity of the car.
Force, F = ma
![F=\dfrac{m(v-u)}{t}\\\\v-u=\dfrac{Ft}{m}\\\\v=\dfrac{Ft}{m}+u\\\\v=\dfrac{-8000\times 0.8}{1110}+21\\\\v=15.23\ m/s](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bm%28v-u%29%7D%7Bt%7D%5C%5C%5C%5Cv-u%3D%5Cdfrac%7BFt%7D%7Bm%7D%5C%5C%5C%5Cv%3D%5Cdfrac%7BFt%7D%7Bm%7D%2Bu%5C%5C%5C%5Cv%3D%5Cdfrac%7B-8000%5Ctimes%200.8%7D%7B1110%7D%2B21%5C%5C%5C%5Cv%3D15.23%5C%20m%2Fs)
So, the final velocity of the car is 15.23 m/s.
Answer:
Pilots depend on the precision of INSTRUMENT LANDING SYSTEMS to guide them when they have limited visibility.
Explanation:
A pilot is a professionally trained individual that has the ability to control an aircraft following directions from a flight control.
Instrument landing system is a guidance system that makes available an instrument based procedures for guiding the pilot of an aircraft to approach and land safely. This system guides the pilot during unfavorable conditions such as low visibility through the use of radio signals.
There are two types of guidance provided by this system:
-> Lateral guidance subsystem and
-> Vertical guidance subsystem.
Lateral guidance subsystem prevents the aircraft approaching a runway to shift laterally from the path recommended.
Vertical guidance subsystem prevents the aircraft approaching a runway to shift laterally from the recommended path.