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xenn [34]
3 years ago
15

Please answer ASAP, and please don't joke around and actually do answer my question. I will give you brainliest if you answer it

well:
A girl, standing on a bridge, throws a stone vertically downward with an initial velocity of 12.0 m/s, into the river below. If the stone hits the water 2.50 seconds later, what is the height of the bridge above the water?
Remember to identify all your data, write the equation, and show your work.
Physics
1 answer:
hammer [34]3 years ago
8 0

Answer:

30 feet

Explanation:

First off, if they are throwing at 12.0 m/s and it takes 2.5 seconds. It will be the act of multiplication.

12 times 2.5 is 30, because 12 times 2 is 24 plus 12 divided by 2 which is 6 so 24 plus 6 is 30.

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The acceleration of a particle traveling along a straight line isa=14s1/2m/s2, wheresis in meters. Ifv= 0,s= 1 m whent= 0, deter
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Answer:

0.78m/s

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We know that

a=\frac{dv}{dt}=\frac{dv}{ds}\times \frac{ds}{dt}=\frac{dv}{ds}v

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\frac{v^2}{2}=0.25\times \frac{2}{3}(s^{\frac{3}{2})^{s}_{1}

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