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maw [93]
2 years ago
12

4. if the experiment had been repeated with frequencies 10 times lower than those in table 5.2,

Physics
1 answer:
Rashid [163]2 years ago
6 0

If the experiment had been repeated with frequencies 10 times lower than those in table 5.2, then Vc will increase 10 times to the values given in the table.

<h3 /><h3>What is frequency?</h3>

It is the number of oscillations per second of the sinusoidal wave.

Vc is the voltage across the capacitor and Xc is the capacitive reactance.

Xc = - 1/2πfC

where f is the frequency and C is the capacitance of the capacitor.

If the frequency is lowered, the potential difference will increase because frequency is inversely proportional to the voltage.

Thus, Vc will increase by lowering the frequency by 10 times.

Learn more about frequency.

brainly.com/question/13758580

#SPJ1

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The ability of singers to shatter glass is due to the control of frequency in their voices. The sound waves will vibrate the air particles that surround the glass at its resonant frequency. The glass will break if a singer sings too loudly.
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3 years ago
How high will a 0.345 kg rock go if thrown straight up by someone who does 111 J of work on it? Neglect air resistance.
Eddi Din [679]

To solve this problem we will apply the concepts related to energy conservation. Here we will understand that the potential energy accumulated on the object is equal to the work it has. Therefore the relationship that will allow us to calculate the height will be

W = PE

W = mgh

Here,

m = mass

g = Acceleration due to gravity

h = Height

our values are,

m = 0.345 kg

g = 9.8m/s^2

W = 111J

Replacing,

W =mgh

111 = (0.345)(9.8)h

h = 32.83m

Then the height is 32.83m.

7 0
3 years ago
A heat engine is 20% efficient. If it loses 800 J to the cooling system and exhaust during each cycle, the work done by the engi
Maurinko [17]

Answer: A. 200J

Therefore, the workdone by the heat engine is 200J

Explanation:

Given ;

The efficiency of the heat engine is E = 20% = 0.2

Heat loss L= 800J

For an heat engine the efficiency is measured by the amount of workdone by the heat engine when compared to the heat generated.

Efficiency E = workdone/heat generated × 100%

Heat generated G= workdone W + heat loss L

G = W + L

According to the question.

W = 20% of G

W = 0.2G ......1

L = 80% of G

L = 0.8G

G = L/0.8 ......2

Substituting equation 2 to 1

W = 0.2(L/0.8)

And L = 800J

W = 0.2(800/0.8)

W = 200J

Therefore, the workdone by the heat engine is 200J

4 0
3 years ago
You are working at a company that manufactures electrical wire. Gold is the most ductile of all metals: it can be stretched into
devlian [24]

Answer:R=1.424 M\Omega

Explanation:

Given

mass of gold m=1.6 gm

Length of wire L=2.2 km

Resistivity of gold \rho =2.44\times 10^{-8}

density of gold =19.3\times 10^3 kg/m^3

and mass=volume\times density

1.6\times 10^{-3}=volume\times 19.3\times 10^3

volume=8.29\times 10^{-8} m^3

And Resistance R=\frac{\rho L}{A}

also be written as

R=\frac{\rho L^2}{V}

where L=length

V=volume

\rho =resistivity\ of\ gold

R=\frac{2.44\times 10^{-8}\times (2200)^2}{8.29 \times 10^{-8}}

R=1.42\times 10^{6} \Omega

R=1.424 M\Omega

5 0
3 years ago
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