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____ [38]
3 years ago
9

You push on a box and are unable to move it. What force opposes your push

Physics
1 answer:
Molodets [167]3 years ago
7 0
<span> static friction :) your very welcome

</span>
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Does every scientific method begin with an observation? explajn.
Alla [95]

yes, because you have to observe your experiment while doing it in case something goes wrong

8 0
3 years ago
Someone help me haha;(
Nikitich [7]

Answer: vf = 51 m/s

d = 112 m

Explanation: Solution attached:

To find vf we use acceleration equation:

a = vf - vi / t

Derive to find vf

vf = at + vi

Substitute the values

vf = 3.5 m/s² ( 8.0 s) + 23 m/s

= 51 m/s

To solve for distance we use

d = (∆v)² / 2a

= (51 m/s - 23 m/s )² / 2 ( 3.5 m/s²)

= (28 m/s)² / 7 m/s²

= 784 m/s / 7 m/s²

= 112 m

6 0
3 years ago
If planet A is four times as far from the sun as planet C, then the period of its orbit will be__ times as long
Burka [1]
Within the system of the same star, the period of a planet's orbit is
proportional to the 3/2 power of its distance from the central body.
(Kepler's empirical third law of planetary motion, promoted to being
etched in stone by Newton's gravitation.)

(4) ^ 3/2 = <em>8 times</em> as long.
4 0
4 years ago
In Fig., block 1 of mass m1 slides from rest along a frictionless ramp from height h = 2.50 m and then collides with stationary
Evgesh-ka [11]

Answer:

Explanation:

Given

initial height h=2.5 m

m_2=2m_1

coefficient of static friction \mu =0.5

When collision is elastic respective velocities after collision is

v_1=\frac{u_1(m_1-m_2)+2m_2u_2}{m_1+m_2}

v_2=\frac{u_2(m_2-m_1)+2m_1u_1}{m_1+m_2}

where u_1 and u_2=initial velocities of object

v_1 and v_2 final velocities of object

u_1=\sqrt{2\times 9.8\times 2.5}

u_1=7 m/s

v_2=\frac{0+2m_1\times 7}{m_1+2m_1}

v_2=\frac{14}{3} m/s

using v^2-u^2=2 as

0-(4.67)^2=2\times (-0.5\times 9.8)\times s

s=2.22\ m

(b)Completely Inelastic

In Completely Inelastic objects stick with each other

m_1u_1=(m_1+m_2)v

v=\frac{u_1}{3}=\frac{7}{3} m/s

using v^2-u^2=2 as

0-(2.33)^2=2\times (-0.5\times 9.8)\times s

s=0.55\ m                          

7 0
4 years ago
Which of the following is the best example of kinetic energy being transformed into potential energy
poizon [28]

A pendulum is probably the most common showing of this example. As the pendulum swings down, it converts its potential energy (height) into kinetic energy (velocity). At the lowest point the kinetic energy is the highest and the potential is the lowest. At the highest point in its swing the velocity is zero so the kinetic energy is zero and the potential energy is at a maximum (greatest height).

3 0
4 years ago
Read 2 more answers
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