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valentina_108 [34]
3 years ago
5

If the age of brother A is 3 years which is half of brother B i.e 6 years then what will be the age of brotherA when brother B i

s 60 years?
Mathematics
2 answers:
saw5 [17]3 years ago
6 0

The older brother was born three years before the young one, which means that their age will always differ by 3. Don't be fooled by the fact that, in this particular year, the age of the older brother is exactly twice the age of the younger! This is not a property that will be carried on with the years: for example, next years bother A will be 4 and brother B will be 7, and 4 is not half of 7!

So, since the property that remains constant is the three year gap, when brother B (the older one) will be 60 years old, brother A will be 3 years younger, as always, which means that he will be 57.

Allushta [10]3 years ago
5 0

Answer: Brother A will be 57 when brother B is 60.

Step-by-step explanation:

Brother A was 3 when Brother B was 6, which means that Brother A is 3 years younger than Brother B.

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A retangle has an area of 30 square meters and a perimeter of 34 meters what are the dimensions of the retangle
s344n2d4d5 [400]

Answer: Length = 15 meters

Width = 2 meters

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

Area of a rectangle = l × w

where l = length

w = width

Therefore,

2l + 2w = 34 ...... i

l × w = 30 ........ ii

From equation i

2l + 2w = 34

Divide through by 2.

l + w = 17 ...... iii

Then, l = 17 - w ........ iv

Put equation iv into ii

l × w = 30

(17 - w) × w = 30

17w - w² = 30

w² - 17w + 30 = 0

w² - 15w - 2w + 30 = 0

w(w - 15) - 2(w - 15) = 0

(w - 2) = 0

w = 0 + 2 = 2

w - 15 = 0

w = 0 + 15 = 15

Length = 15 meters

Width = 2 meters

6 0
3 years ago
Find surface area of rectangular prism
DIA [1.3K]

Answer:

806 yd sq.

Step-by-step explanation:

Area=(length)(width), so to find the surface area you can just find the area of each side and then add then all together.

They already gave you the length of some of the sides, so you should use that to help you find the length of all the sides.

You can see the entire prism's length is 17 yd, width is 4 yd, and height is 14 yd.

The large visible side's area would be (14)(17)= 283 yd. There's another one of these side's on the other side that we can't see. So we would do (283)(2) = 566 yd sq.

Next, we'll find the area of the side on the side by doing (14)(4)=56. Once again, there's two of these sides so we do (56)(2) to get 112 yd sq for this side.

Finally, we'll find the area of the top side. We can do (4)(17) =68, and then (68)(2) to get 138 yd sq.

Now, we have the area of each side of the prism! To find the total surface area, just add them all together. 556+112+138=806.

The surface area would be 806 yd sq.

5 0
2 years ago
The hypotenuse of a right triangle measures 58 cm and one of its legs measures 42 cm. What is the length of the missing leg? 10
Nutka1998 [239]
If the hypotenuse is 58cm, and one of the others legs is 42cm the answer would be 40cm

Explanation:

Here you have to use the formula

{a}^{2} + {b}^{2} = {c}^{2}
Then you have to pose the formula in terms of one of the legs, so:

{a}^{2} = {c}^{2} - {b}^{2}
a = \sqrt{ {c}^{2} - {b}^{2}}
So when you change the letter for numbers you have that:

a = \sqrt{ {58}^{2} - {42}^{2} }

a=40
5 0
3 years ago
Hans's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Hans
Tanya [424]
He used 53 pounds. I got this by using two equations.
a+b=117
and
5.8a+4.1b= 569.8

I took the first equation and subtracted 'b' so the equation looked like a=117-b.
I then plugged in 117-b into the second equation, so it ended up looking like this:
5.8 (117-b)=569.8
5.8 times 117 is 678.6. And 5.8 times negative b is negative 5.8b.
The equation now looks like this:
678.6-5.8b+4.1b=569.8
Add like terms
678.6-1.7b=569.8
Then subtract 678.6 from both sides
-1.7b= -108.8
divide each side by -1.7
you get b= 64.
But because you are looking for how many pounds for a, subtract 64 from 117. You get 53. 53 is the answer.
3 0
3 years ago
I need help with this question
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