D=426-48(21)
I got 18 days.
So, D=18
Hope this helps! :)
Fourth one since x is 2 and the y is 1
Use A = P(1+r/n)^(nt).
Here, A = $3000(1+0.07/12)^(12*6). Can you evaluate this?
Median is generally good if you have outliers (data points that are very far off from the majority of the points).
Mean can be used otherwise.
Answer:
And the confidence interval would be between (3.035;3.365)
Step-by-step explanation:
Information given
represent the sample mean
population mean (variable of interest)
s=0.8 represent the sample standard deviation
n=40 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
(1)
The degrees of freedom are given by:
The Confidence level is 0.80 or 80%, the significance would be
and
, and the critical value would be
Now we have everything in order to replace into formula (1):
And the confidence interval would be between (3.035;3.365)