Answer:
A. 0.806 kN
B. 0.303 kN
Explanation:
<h3>A.</h3>
The kinetic energy of the ball is ...
KE = 1/2mv² = 1/2(0.206 kg)(18 m/s)² = 33.372 J
The work required to reduce this to zero over a distance of 4.14 cm is ...
W = Fd
F = W/d = (33.372 J)/(0.0414 m) = 0.806 kN
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<h3>B.</h3>
When the distance is 11 cm, the force is ...
F = (33.372 J)/(0.11 m) = 0.303 kN
Answer:
Look below
Explanation:
Units are very important. Let's say we were building an apartment. We used meters for every measurement except for 1 support where we used centimeters. This could lead to the collapse of the whole structure as the measurements were wrong. 100 meters and 100 centimeters are very different.
Answer:
a = g (m₂ -m₁ sin θ) / (m₁ + m₂)
Explanation:
To solve this we must locate a reference system in the inclined plane, in this case the axis eg. it is parallel to the plane and the axis and is perpendicular to the plane, we take the direction to the right as positive.
Let's write Newton's second law for block 1 on the plane
X axis
T - Wₓ = m₁ a
Y Axis
N – = 0
We use trigonometry to find the components of the weight
sin θ = Wₓ / W
Wₓ = W sin θ
cos θ = W_{y} / W
W_{y}= W cos θ
We substitute
T - m₁ g sin θ = m₁ a
N = m₁ g cos θ
We write Newton's equations for block 2 that is hanging.
Note that if block 1 goes up, block 2 must go down, therefore for this block the positive direction is down.
W₂ - T = m₂ a
Let's write the system of equations
T - m₁ g sin θ = m₁ a
m₂ g - T = m₂ a
Let's add
m₂ g - m₁ g sin θ = (m₂ + m₁) a
a = g (m₂ -m₁ sin θ) / (m₁ + m₂)
Acceleration is the same for both blocks as they are connected by a rope