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Monica [59]
3 years ago
9

Can you help please

Physics
1 answer:
Minchanka [31]3 years ago
5 0

Answer:

yes the answer to this question you find if you call this number 405 900 2420

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What is 20kg x 9.8m/s2
trasher [3.6K]

Use newton's second law: net force = m*a

in this case, m is 20kg and a is g. The net Force would be 196 Newtons

4 0
3 years ago
Debby and Ben took different routes to travel from Point A to Point E. Debby took the route along A, B, C, D, and E. Ben took th
svetlana [45]

Answer:

Ben's average speed was twice Debby's average speed.

Explanation:

Ben covered a total distance of 16 miles (10+4+2) and Debby covered 8 miles (3+2+2+1) which is half of what Ben covered. As they both reached the place in the same amount of time it tells us Ben was faster.

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3 years ago
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Upthrust given by Water to the body
erica [24]

Answer:

According to Archimedes principle the upthrust on the body is equal to the weight of the water displaced by the body. ... Here, the mass would be the net difference in the weight of the object.

7 0
3 years ago
If Planet Y orbits the Sun but does not rotate on its axis at all, how long would a day be on Planet Y?
scoundrel [369]

A day which in this case is longer than a year

4 0
3 years ago
If an object falls and ends with a velocity of 58.8 m/s, how long was the<br><br> object falling?
tensa zangetsu [6.8K]

Answer:

the time taken for the object to fall is 6 s.

Explanation:

Given;

final velocity of the object, v = 58.8 m/s

initial velocity of the object, u = 0

The height of fall of the object is calculated as;

v² = u² + 2gh

v² = 2gh

h = \frac{v^2}{2g} \\\\h = \frac{(58.8)^2}{2(9.8)} \\\\h = 176.4 \ m

The time to fall through the height is calculated as;

h =ut+  \frac{1}{2} gt^2\\\\h = 0 +  \frac{1}{2} gt^2\\\\h =  \frac{1}{2} gt^2\\\\t= \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 176.4}{9.8} } \\\\t = 6 \ s

Therefore, the time taken for the object to fall is 6 s.

6 0
3 years ago
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