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mrs_skeptik [129]
3 years ago
11

A wire that is 0.20 meters long is moved perpendicularly through a magnetic field of strength 0.45 newtons/amperes·meter at a sp

eed of 10.0 meters/second. What is the emf produced?
Physics
2 answers:
zloy xaker [14]3 years ago
8 0
Given:
length of the wire = 0.20 meters
magnetic field strength = 0.45 newtons/amperes meter
speed = 10.0 meters per second

emf = B * l * v 
B = flux density ; l = length of the wire ; v = velocity of the conductor

emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds
emf = 0.90 volts

The emf produced is 0.90 volts.


Blizzard [7]3 years ago
3 0
THE ANSWER IS c☺ #platousers100%
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If you're on the orbiting International Space Station with a box of feathers and a box of sand, how could you tell which is whic
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Answer:

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6 0
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Read 2 more answers
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azamat

Answer:

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solution

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q = 1.622 m

so length of selfie-stick is 1.62 m

4 0
4 years ago
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