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weqwewe [10]
3 years ago
5

A catcher “gives” with the ball when he

Physics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

  A. 0.806 kN

  B. 0.303 kN

Explanation:

<h3>A.</h3>

The kinetic energy of the ball is ...

  KE = 1/2mv² = 1/2(0.206 kg)(18 m/s)² = 33.372 J

The work required to reduce this to zero over a distance of 4.14 cm is ...

  W = Fd

  F = W/d = (33.372 J)/(0.0414 m) = 0.806 kN

__

<h3>B.</h3>

When the distance is 11 cm, the force is ...

  F = (33.372 J)/(0.11 m) = 0.303 kN

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A small rocket with mass 20.0 kg is moving in free fall toward the earth. Air resistance can be neglected. When the rocket is 80
Mekhanik [1.2K]

Answer:

= 308.5 N

Explanation:

acceleration  of rocket for safe landing

v_{y} ^{2} = v_{0} ^{2} +2ay

a = \frac{v_{y}^{2} - v_{0}^{2}  }{2y}

v_{0} = initial velocity

v_{y} =final Velocity

m = mass of rocket

\frac{0^{2} - 30^{2}  }{2\times80}

-5.625 m/s^{2}

Upward force

F - mg = ma

F = ma+ mg

F = m(a+g)

m= mass

a = 5.625 m/s^{2}

g = 9.8m/s^{2}

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7 0
3 years ago
PLX HELP
Gnesinka [82]

The answer to this question is A.

3 0
4 years ago
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Which of the following statement is false
guajiro [1.7K]
There is nothing to choose from
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3 years ago
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A physical representation of a real object, such as a globe of the world, is an ___ model
densk [106]

Answer;

-Physical model

A physical representation of a real object, such as a globe of the world, is a physical model.

Explanation;

-A physical model is a simplified material representation, usually on a reduced scale, of an object or phenomenon that needs to investigated.

-The model can be used to simulate the physical conditions involved (temperature, waves, speed etc.) and to predict the particular constraints of the situation.


5 0
3 years ago
a 10 kg solid disk of radius 0.5 m is rotated about an axis through its center.the disk accelerates from rest to angular speed o
mezya [45]

Answer:

τ ≈ 0.90 N•m

F =

Explanation:

I = ½mR² = ½(10)0.5² = 1.25 kg•m²

α = ω²/2θ = 3.0² / 4π = 0.716... rad/s²

τ = Iα = 1.25(0.716) = 0.8952... ≈ 0.90 N•m

τ = FR

Now we have the unanswered question of reference frame.

80° from what?

If it's 80° from the radial

F = τ/Rsinθ = 0.90/0.5sin80 = 1.818...  ≈ 1.8 N

If it's If it's 80° from the tangential

F = τ/Rcosθ = 0.90/0.5cos80 = 10.311...  ≈ 10 N

There are an infinite number of other potential solutions

7 0
3 years ago
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