Answer:
Explanation
Given that 36% are recessive in traits
100-36 = 64% for dominant traits considering a whole population to be 100%
P=dominant allele
q= recessive allele
P2= dominant genotype
q2= recessive genotype
according to hardyweinberg principle, p+q=1
64/100= 0.64 frequency for dominant traits or genotype, therefore
p2=0.64
then
P=√0.64
p= 0.8
Therefore, dominant allele frequency (p) for the population is 0.8
Explanation:
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