<span>Inference because she drew a conclusion based on evidence.</span>
2C₃H₆ + 9O₂ ------> 6CO₂ + 6H₂O
moles of C₃H₆ =
=
= 0.995 mol
ratio of C₃H₆ : O₂
2 : 9
∴ mol of O₂ =
= 4.479 mol
Mass of O₂ = (Molar Mass) * (Mole)
= (16 * 2) g/mol * (4.479)mol
= 143.31 g
Answer:
The value for this reaction at 1181 K is .
Explanation:
The expression of an equilibrium constant in terms of partial pressure can be given as:
Total pressure of the gases at equilibrium = P = 69.4 Torr
Partial pressure of hydrogen gas =
Partial pressure of water vapor =
(Dalton's law of partial pressure)
x = 69.4 Torr - 53.7 Torr = 15.7 Torr
The value for this reaction at 1181 K is .