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2 years ago

7

How many molecules are in

1 answer:

Olin [163]2 years ago

5 0

It’s B
Because 6.02

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Identify the conjugate base in each pairs

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Answer: 1) $RCOO^-$

2) $H_2PO_4^-$

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Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

1) $RCOOH\rightarrow RCOO^-+H^+$

Here, $RCOOH$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $RCOO^-$ which is a conjugate base.

2) $H_3PO_4\rightarrow H_2PO_4^-+H^+$

Here, $H_3PO_4$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $H_2PO_4^-$ which is a conjugate base.

3) $RNH_3^+\rightarrow RNH_2+H^+$

Here, $RNH_3^+$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $RNH_2$ which is a conjugate base.

4) $H_2CO_3\rightarrow HCO_3^-+H^+$

Here, $H_2CO_3$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $HCO_3^-$ which is a conjugate base.

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