Your measurement implies that the range of answers is 128.6 mL to 128.8 mL.
If you do not state explicitly the range of uncertainty (e.g., ± 0.5 mL), the <em>implied range of uncertainty</em> is ±1 in the last significant digit.
Thus, a reading of 128.7 mL implies that the volume is 128.7 mL ± 0.1 mL.
The ammonia gas, having a lower molecular weight than the hydrogen chloride, will diffuse faster and travel a greater length of the tube. Consequently, the white ring of ammonium chloride will form much closer to hydrochloric acid end of the tube. Which in conclusion your answer will be D :)
Answer:
<h3>0.2498mol

</h3>
Explanation:
7gN2 x 
=0.2498mol N2
Nitrogen gas has the formula
so therefore that means you would have to multiply the mass in the molar by 2. To solve for the number of moles you need to cancel out the grams, you do this by using the molar mass of nitrgoen gas. You get the value on in the denominator from the periodic table (atomic mass of element). The grams will cancel out, leaving you with the number of moles when you divide 7/2(14.01).
Answer:
(a) 133.33nm
(b) 600nm
(c) 7,600nm
Explanation:
The concentration of Y can be determined by using the formula:
![Y = \dfrac{[L]}{k_d+[L]}](https://tex.z-dn.net/?f=Y%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7Bk_d%2B%5BL%5D%7D)
where;
[L] = concentration of the binding ligand.
kd = 400 nm
Thus:
When Y = 0.25; we get :
![0.25 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.25%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.25 (400 + [L]) = [L]
100 + 0.25[L] = [L]
100 = [L] - 0.25 [L]
100 = 0.75 [L]
[L] = 100/0.75
[L] = 133.33 nm
At, Y = 0.6
![0.6 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.6%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.6 (400 + [L]) = [L]
240 + 0.6[L] = [L]
240 = [L] - 0.6 [L]
240 = 0.4 [L]
[L] = 240/0.4
[L] = 600 nm
At, Y = 0.95
![0.95 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.95%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.95 (400 + [L]) = [L]
380 + 0.95[L] = [L]
380 = [L] - 0.95 [L]
380 = 0.05 [L]
[L] = 380/0.05
[L] = 7600 nm
Answer:
Red
Explanation:
Red color is evidenced when thymol blue indicator is in a solution having a pH of 11. A pH of 11 means that the solution is basic or alkaline. Therefore, the indicator turns red, indicating that the solution is alkaline.
When thymol blue indicator is in a acidic solution, the indicator remains blue.