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3 years ago

A

Chemistry

1 answer:

DIA [1.3K]3 years ago

5 0

V_1=49.8mL
T_1=18°C=291K
T_2=83°C=356K

Using Charles law

$\\ \sf\longmapsto V_1T_2=V_2T_1$

$\\ \sf\longmapsto V_2=V_1T_2\div T_1$

$\\ \sf\longmapsto V_2=\dfrac{49.8(356)}{291}$

$\\ \sf\longmapsto V_2=\dfrac{17728.8}{291}$

$\\ \sf\longmapsto V_2=60.9mL$

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How many liters of oxygen gas, at standard

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Answer:

Explanation:

For the balanced reaction:

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It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.

Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:

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Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:

Using cross multiplication:

4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.

0.64 mol of Fe is needed to react with → ??? mol of O₂.

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1 mol of O₂ occupies → 22.4 L, at STP conditions.

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3 years ago

Draw all four products obtained when 2-ethyl-3-methyl-1,3-cyclohexadiene is treated with HBr at room temperature and show the me

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Answer:

See explanation below

Explanation:

In this case we have reaction of addition. In this case a diene reacting with an acid as HBr. This reaction is known as Hydrohalogenation, and, as we have a diene, this kind of reaction can be done as 1,4 addition. Which means that the reaction will be undergoing with an adition in the carbon 1, and carbon 4.

At room temperature we can expect that this reaction can be done in thermodynamic conditions, Now, as the problem states that is forming 4 products, we can expect products of a 1,2 addition too. This product can be formed if the reaction is taking place in the most stable carbocation, and then, by resonance, we can expect the 1,4 product too.

Now, the HBr can be attacked by the double bond of the first position, giving two possible products or by the double bond of the third position giving the other two products. These products are all possible, obviously the most stable will be the major of all of them, but the other three are perfectly possible. One product is formed without doing much, and the other by resonance. Same happens with the other double bond.

In the picture below, you have the mechanism for all the 4 products.

Hope this helps

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3 years ago

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Answer:

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1 year ago

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3 years ago