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3 years ago

PLEASE HELP WILL GIVE BRAINLEIST ANSWER AND STARS AND THANK BOTH ON YOUR PROFILE AND ANSWER!!!!!!!!!!!!!!!!

Mathematics

2 answers:

TEA [102]3 years ago

6 0

The answer is -102
if you are on a computer, there is a built in calculator you could use for problems like this

Karo-lina-s [1.5K]3 years ago

4 0

Hello there.

-23 is correct.

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The three side lengths of four triangles are given which triangle is a right triangle

Whitepunk [10]

Answer:

Triangle 3: 3, 4 ,5

Step-by-step explanation:

Well, you can easily tell by 3, 4, 5 being a Pythagorean triple.

But you have to use the Pythagorean Theorem to solve this.

So you get the side lengths of the two shortest sides, and you add the squared versions of them together.

So: 3^2+4^2 and if that equals the biggest side:5^2 then it's a right triangle.

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3 years ago

Jordan received 9 text messages last week.She received 3 times more text message this week than last week. How many text message

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If she got 9 messages last week and 3rimes as much this week then she got 27 messages because 9x3=27

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3 years ago

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Temka [501]

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3 years ago

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adell [148]

850/630= 1.35 exchange rate

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4 years ago

PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!

pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

In this problem, we have that the sine is given by:

$\sin{\theta} = \frac{1}{3}$

Hence, applying the identity, the cosine is given as follows:

$\cos^2{\theta} = 1 - \sin^2{\theta}$

$\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2$

$\cos^2{\theta} = 1 - \frac{1}{9}$

$\cos^2{\theta} = \frac{8}{9}$

$\cos{\theta} = \pm \sqrt{\frac{8}{9}}$

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

The tangent is given by the sine divided by the cosine, hence:

$\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

$\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}$

$\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0

2 years ago