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natta225 [31]
3 years ago
13

PLEASE HELP WILL GIVE BRAINLEIST ANSWER AND STARS AND THANK BOTH ON YOUR PROFILE AND ANSWER!!!!!!!!!!!!!!!!

Mathematics
2 answers:
TEA [102]3 years ago
6 0
The answer is -102 
if you are on a computer, there is a built in calculator you could use for problems like this
Karo-lina-s [1.5K]3 years ago
4 0
Hello there.


-23 is correct.
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En las olimpiadas matemáticas,la hora de inicio del evento se expresa en una ecuación simple: 2x+6=x+17 ¿A qué hora empezó el ev
Sergio [31]

Answer:

11 minutos.

Step-by-step explanation:

En las Olimpiadas de Matemáticas, la hora de inicio del evento se expresa en una ecuación simple: 2x + 6 = x + 17 ¿A qué hora comenzó el evento?

La hora en que comienza el evento en los juegos olímpicos se representa como x

Por tanto: 2x + 6 = x + 17

Recopilar términos similares

2x - x = 17 - 6

x = 11 minutos

Por lo tanto, los eventos comienzan en 11 minutos.

7 0
3 years ago
What is 4²(4²)? <br> 2. 5⁴(5)÷2¹? <br> 3. (5+3)²? <br> Solve the following expressions
Nat2105 [25]

Answer:

256, 3125/2, 64

Step-by-step explanation:

4^2(4^2)=16(16)=256

5^4(5)/2^1=625(5)/2=3125/2

(5+3)^2=8^2=8*8=64

7 0
3 years ago
Combine like terms.
Ivahew [28]
The answer is going to be c because 12-35=23 and since there is variables you have to add the variable.
5 0
3 years ago
Read 2 more answers
PLEASE HELP I WILL MARK YOU BRAINLIEST
kakasveta [241]

Answer:

84 square centimetres

Step-by-step explanation:

Split the figure into multiple smaller figures. Then multiply the side lengths and add them all together.

6 0
3 years ago
Read 2 more answers
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
2 years ago
Read 2 more answers
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