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Vanyuwa [196]
3 years ago
5

Which of the following is an adaptation found in many desert plants? A. large, flat leaves B. dormant period during the winter C

. fuzzy growth on leaves D. wide-spreading, shallow roots
Chemistry
2 answers:
Musya8 [376]3 years ago
8 0
I say D wide spreading, shallow roots
frosja888 [35]3 years ago
4 0
I'd say the answer is D because they need to intake and keep as much water as possible.
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Why do you elements in the same group have similar properties
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Answer:

They have similar properties, because they share similar amounts of electrons in their outer shell, valence electrons! This means they will only be able to interact with other elements with those electrons so they often show similar properties.

Explanation:

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Which of the following statements are not scientific hypotheses?
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calcium has atomic number of 20 how many electrons of a calcium atom are involved in chemical bonding
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The answer is 2 electrons.


The electron configuration of calcium is 2:8:8:2

Calcium has two electrons in its outermost shell. These are its valence electrons and are the ones used in bonding with other elements.  Valence electrons of an atom are those electrons that are in its outer energy shell or that are available for bonding.

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For example, when calcium metal reacts with chlorine gas,   calcium gives up its two valence electrons and Chlorine accepts them resulting in a new substance called calcium chloride in which the two elements have ended up forming ionic bonds.

 


7 0
3 years ago
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if 45.0 ml of 1.50 M Ca(OH)2 are needed to neutralize 25.0 ml of HI of unknown concentration, what is the molarity of the HI?
ipn [44]

Answer:

M of HI = 5.4 M.

Explanation:

  • We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

<em>(XMV) acid = (XMV) base.</em>

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

<em>(XMV) HI = (XMV) Ca(OH)₂.</em>

For HI; X = 1, M = ??? M, V = 25.0 mL.

For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.

<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>

6 0
3 years ago
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