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Vanyuwa [196]
3 years ago
5

Which of the following is an adaptation found in many desert plants? A. large, flat leaves B. dormant period during the winter C

. fuzzy growth on leaves D. wide-spreading, shallow roots
Chemistry
2 answers:
Musya8 [376]3 years ago
8 0
I say D wide spreading, shallow roots
frosja888 [35]3 years ago
4 0
I'd say the answer is D because they need to intake and keep as much water as possible.
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Show all calculations. 1. 2 C 4 H 10 + 13 O 2 -> 8 CO 2 + 10 H 2 O a) what mass of O 2 will react with 400 g C 4 H 10? b) how
bazaltina [42]

\\ \tt\hookrightarrow 2C_4H_10+13O_2\longrightarrow 8CO_2+10H_2O

  • 13mol of O_2 reacts with 2mols of C_4H_10.
  • 7.5mol of O_2 reacts with 1mol of C_4H_10

No of moles:-

\\ \tt\hookrightarrow \dfrac{Given\:mass}{Molar\:mass}

\\ \tt\hookrightarrow \dfrac{400}{58}

\\ \tt\hookrightarrow 6.89mol

Now

Moles of O_2

\\ \tt\hookrightarrow 7.5(6.89)=51.6mol

Mass of O_2

\\ \tt\hookrightarrow 51.6(32)=1651.2g

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2 years ago
A scientist has found two samples of radioactive material. The first sample has a mass of 1.0 g and an activity of 2.0 mc022-1.j
Degger [83]
1.5 g is your answer 
4 0
3 years ago
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For a particular reaction, ΔH = -99.84 kJ and ΔS = -16.80 J/K. Calculate ΔG for this reaction at 298 K.
marta [7]
To solve this given problem,  we can use the equation below:
ΔG=ΔH - T*ΔS

We are information and values are given and can be used in solving the ΔG of this particular reaction.
ΔH=-99.84kJ
ΔS=-16.80 J/K
T=298K

ΔG=(-99.84kJ)-(298K*-16.80J/K)
ΔG=-94.83kJ

The answer for ΔG is -94.83kJ.
7 0
3 years ago
How do forces between particles in gases compare to forces in the other
Ber [7]

Answer:

A. The forces in gases are weaker than forces in solids but stronger

than forces in liquids.

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AnnyKZ [126]

Answer:

Is a substance that can maintain  certain range of pH

Explanation:

A buffer is mixture of two salts that are complementary, one salt is acid and another is basic, but since then share some part of their structure, if you add to this mixture another acid, the basic salt can absorb it and still maintaining the same pH. If you pour a base, the acid salt will absorb it and again the final pH will remain the same. So the buffers are used to maintain the same pH does not matter if you add small quantities of an acid or base.

5 0
3 years ago
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