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sveticcg [70]
3 years ago
8

When was the first published textbook containing a table identifying the first 33 elements

Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
5 0

1789 -- raité élémentaire de chimie is a textbook written by Antoine Lavoisier published in 1789 and translated into English by Robert Kerr in 1790 under the title Elements of Chemistry

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Ethylene glycol (C2H6O2) is used as an antifreeze in cars. If 250 g of ethylene glycol is added to 3.00 kg of water, what is the
Zepler [3.9K]

Answer:

2,909 M

Explanation:

molair mass is of.ethylene is 26,04 g/mol

first you need to calculate how much mL 3 kg is. You can do this by using the density of ethylene: 1,1 g/mL.

3000 g x 1.1 = 3300 mL = 3,3 L

Next you need to calculate the amount of moles:

250 g / 26,04 g/mol = 9,60 mol

Now you can calculate the molarity:

9,6/3.3 = 2,909 M

I don't know the answer for the second question. I'm sorry.

3 0
3 years ago
The average atomic mass of Eu is 151.96 amu. There are only two naturally occurring isotopes of europium, Eu with a mass of 151.
earnstyle [38]

Answer:

The percentage abundance of Eu isotopes are 52 %  and 48 % .

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope,:

% = x %

Mass = 151.0 amu

For second isotope :

% = 100  - x  

Mass = 153.0 amu

Given, Average Mass = 151.96 amu

Thus,

151.96=\frac{x}{100}\times {151.0}+\frac{100-x}{100}\times {153.0}

Solving for x, we get that:

x = 52 %

<u>Thus percentage abundance of Eu isotopes are 52 %  and 48 % .</u>

7 0
3 years ago
Find the weight of HNO_3 present in 20ml, 0.30 N
yanalaym [24]

Answer:

mass of HNO₃ = 0.378 g

Explanation:

Normality = Molarity * number of equivalents

Molarity = Normality/number of equivalents

normality of HNO₃ = 0.30 N, Volume = 20 mL

HNO₃ ionizes in the following way:

HNO₃(aq) ----> H⁺ + NO₃⁻

Therefore, number of equivalents for HNO₃ is 1

molarity of HNO₃ = 0.30/1 =0.30 mol/dm³

Using the formula, molarity = number of moles/volume in liters

number of moles = molarity * volume

Number of moles of HNO₃ = 0.30 mol/dm³ * 20ml * 1 dm³ /1000 mL

number of moles = 0.006 moles

From the formula, mass = number of moles * molar mass

molar mass of HNO₃ = 63.0 g/mol

mass = 0.006 * 63

mass of HNO₃ = 0.378 g

6 0
3 years ago
ASAP PLEASEE
Lesechka [4]

Answer:

Joe Mama Formula

Explanation:

JoeMamic Acid is the answer

4 0
2 years ago
An atom has a mass number of 24 and 13 neutrons. What is the atomic number of this atom? Express
Temka [501]
A=mass number   (protons + neutrons)
Z=atomic number  (protons)
N=number of neutrons.

A=Z+N

Data:
A=24
N=13

Therefore:
24=Z+13
Z=24-13=11

Answer: The atomic number of this atom is 11. (The element is sodium)
8 0
3 years ago
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