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dolphi86 [110]
3 years ago
8

The top of Mount Everest is about 8850 M what would the approximate air temperature be at that altitude

Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
4 0
Close to about -36 degrees Celsius ( - 33 degrees Fahrenheit) in January but can drop to -60 degrees Celsius ( - 76 degrees Fahrenheit).
in July, it can be close to -19 degrees Celsius (- 2 degrees Fahrenheit) 
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In a disproportionation reaction, the disproportionate substance
trapecia [35]

Answer:

The answer is C: has at least three oxidation states.

Explanation:

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Please I really really need help!!!
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Answer:

1) 40

2) 2.25 moles

3) 17

4) 120

5) Fe₂O₃

Explanation:

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Today, nuclear power plants rely on fission. While fusion reactions have been used in nuclear bombs, many scientists and enginee
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Explanation:

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5 0
3 years ago
The complete combustion of propane (C3H8) in the presence of oxygen yields CO2 and H2O: C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (g) a
mixas84 [53]

Answer:

26.9 L is the volume of CO₂, we obtained

Explanation:

The reaction is: C₃H₈(g) + 5O₂(g)  →  3CO₂ (g) + 4H₂O (g)

Let's determine the reactants moles:

27.5 g . 1mol / 44 g = 0.625 moles

We need density of O₂ to determine mass and then, the moles.

O₂ density = O₂ mass / O₂ volume

O₂ density . O₂ volume = O₂ mass

1.429 g/L . 45L = O₂ mass → 64.3 g

Moles of O₂ → 64.3 g . 1mol/32g = 2.009 moles

Let's find out the limiting reactant:

1 mol of propane needs 5 moles of oxygen to react

Then, 0.625 moles will react with (0.625 . 5)/1 = 3.125 moles of O₂

Oxygen is the limiting reactant, we need 3.125 moles but we only have 2.009 moles

Ratio is 5:3. 5 moles of O₂ produce 3 moles of CO₂

Therefore, 2.009 moles of O₂ must produce (2.009 .3) /5 = 1.21 moles of CO₂. Let's find out the volume, by Ideal Gases Law (STP are 1 atm and 273K, the standard conditions)

1 atm . V = 1.21 moles . 0.082 . 273K

V = (1.21 moles . 0.082 . 273K) / 1atm = 26.9 L

3 0
3 years ago
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