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gulaghasi [49]
3 years ago
6

Which of the following aqueous solutions are good buffer systems? . 0.32 M calcium chloride + 0.27 M sodium chloride 0.35 M ammo

nia + 0.36 M calcium hydroxide 0.19 M barium hydroxide + 0.28 M barium chloride 0.12 M hydrofluoric acid + 0.17 M potassium fluoride 0.20 M hydrobromic acid + 0.22 M sodium bromide
Chemistry
1 answer:
irga5000 [103]3 years ago
7 0

Answer:

0.12 M hydrofluoric acid + 0.17 M potassium fluoride

Explanation:

To make a buffer, you must to have an aqueous mixture of a weak acid and its conjugate base or vice versa.

Knowing that:

0.32 M calcium chloride + 0.27 M sodium chloride: <em>is not a good buffer system </em>because CaCl₂ and NaCl are both salts.

0.35 M ammonia + 0.36 M calcium hydroxide <em>is not a good buffer system </em>because ammonia is a weak base but calcium hydroxide is a strong base

0.19 M barium hydroxide + 0.28 M barium chloride <em>is not a good buffer system </em>because Ba(OH)₂ is a strong base.

0.12 M hydrofluoric acid + 0.17 M potassium fluoride <em>is a good buffer system </em>because HF is a weak acid and KF (F⁻ in aqueous medium), is its conjugate base

0.20 M hydrobromic acid + 0.22 M sodium bromide <em>is not a good buffer system </em>because HBr is a strong acid.

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Hello!
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Answer:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.00064M

Explanation:

Hello there!

In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:

K=\frac{[CO][Cl_2]}{[COCl_2]}

Which can be written in terms of x, according to the ICE table:

0.32=\frac{x^2}{0.015M-x}

Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:

[CO]=[Cl_2]=0.01436M

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Regards!

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