Question

Find the empirical formula of the compound containing 2.4 gram of carbon, 6.4 gram of oxygen and 0.2 gram of hydrogen ​

Answer 1

Answer:

Empirical formula= COOH

Step-by-step explanation:

Molecular mass of the elements

Carbon= 12

Oxygen= 16

Hydrogen= 1

We divide the elements each with their molecular formula

Carbon= 2.4/12

Carbon= 0.2

Oxygen= 6.4/16

Oxygen= 0.4

Hydrogen= 0.2/1

Hydrogen= 0.2

Now we divide with the smallest result which is 0.2

Carbon= 0.2/0.2

Carbon = 1

Oxygen= 0.4/0.2

Oxygen= 2

Hydrogen= 0.2/0.2

Hydrogen= 1

So we have

Carbon 1, oxygen 2, hydrogen 1

Empirical formula= COOH