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vovikov84 [41]
3 years ago
13

Find the empirical formula of the compound containing 2.4 gram of carbon, 6.4 gram of oxygen and 0.2 gram of hydrogen ​

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0

Answer:

Empirical formula= COOH

Step-by-step explanation:

Molecular mass of the elements

Carbon= 12

Oxygen= 16

Hydrogen= 1

We divide the elements each with their molecular formula

Carbon= 2.4/12

Carbon= 0.2

Oxygen= 6.4/16

Oxygen= 0.4

Hydrogen= 0.2/1

Hydrogen= 0.2

Now we divide with the smallest result which is 0.2

Carbon= 0.2/0.2

Carbon = 1

Oxygen= 0.4/0.2

Oxygen= 2

Hydrogen= 0.2/0.2

Hydrogen= 1

So we have

Carbon 1, oxygen 2, hydrogen 1

Empirical formula= COOH

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the length of the first side of the triangle is \frac{28}{3}\ in

the length of the second side of the triangle is \frac{37}{3}\ in

the length of the third side of the triangle is \frac{19}{3}\ in

Step-by-step explanation:

Let

x-----> the length of the first side of a triangle

y----> the length of the second side of a triangle

z---> the length of the third side of a triangle

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