Three balloons are inflated to the same size. The three balloons are submerged in buckets filled with ice water, tap water and w
2 answers:
Explanation:
Charles law states that 'at constant pressure Volume occupied by the gas is directly proportional to the Temperature in Kelvins'.
( At constant pressure)
So, when inflated balloon is:
- Submerged in water heated upto 65°C the volume of the of air inside the balloon will increase and so is in the size of balloon.Hence, size will increase.
- Submerged in ice water,the temperature in the water is less that of the temperature of gas inside the balloon.So, with decrease in temperature the volume of the balloon will also decrease.
- Submerged in normal water as there will be not that much temperature difference in water temperature and gas inside the balloon .Hence,no appreciable change in size of balloon will be observed.
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To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency
At the same time we have that
Therefore there is not have same units and both are not consistent and the correct answer is B.
Answer:
The intensity of the net electric field will:
Explanation:
Here we need first find the electric field due to the first charge at the midway point.
The electric field equation is given by:
Where:
- k is Coulomb's constant
- q(1) is 20.00 μC or 20*10⁻⁶ C
- d is the distance from q1 to the midpoint (d=10.0 cm)
So, we will have:
The direction of E1 is to the right of the midpoint.
Now, the second electric field is:
The direction of E2 is to the right of the midpoint because the second charge is negative.
Finally, the intensity of the net electric field will:
I hope it helps you!