Answer: The correct answer is option (A).
Explanation:
Momentum of the car with 0.04 kg mass , which travelling with velocity of 2.00 m/s

Then the maximum speed of the another car in order to not to break the eggs will be same as first car:



Speed slightly more than 1 m/s will increase the momentum of second car and the eggs will break. So, from the given options the minimum speed need by the second car will be 1.42m/s.
Answer: Producers have the greatest amount of available energy.
When an organism eats another organism, it gains energy.
Explanation:
A food chain is a linear sequence of transfer of food and energy when one organism is eaten by the other organism. A food web is the interconnection of two or more food chains. This happens when one organism belong to one food chain also consume organisms of same food chain or other food chain. A food chain includes trophic levels on the basis of the mode of feeding of the living beings.
Among the options given, Producers have the greatest amount of available energy. and
When an organism eats another organism, it gains energy. are correct.
Producers are the organism which are capable of producing their food either through photosynthesis or chemosynthesis. They are present at the base level of the food chain. They consist of large amount of energy as compared to all the trophic levels in the food chain.
When one organism eats other organism it gains energy because of the assimilation and digestion of the organism as food.
<h2>The velocity of car was m m/s </h2>
Explanation:
When the car skids , its centripetal force is provided by frictional force .
Here centripetal force F = 
here v is the velocity of car and r is the radius of the curve .
The frictional force f = μ R
here μ is the coefficient of kinetic friction and R is normal reaction
Thus f = m g
On horizontal road R = mg
Thus F = f at the time of skid .
Thus v = 
=
= 9 m/s
Answer:
the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Explanation:
Given that ;
the top speed of Cheetahs is almost 60 mph
In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2
The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?
From the knowledge of Newton's Law;
we knew that ;
Force F = mass m × acceleration a
Also;
The net force
= frictional force 
so we can say that;
m×a = 
where;
the coefficient of static friction
is:



= 1.94
Hence; the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94