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3 years ago

In the chemical formula 3NH4, how many total atoms of nitrogen (N

2 answers:

8 0

One atom on nitrogen because there isn’t a number directly after it’s the 3 signifies that there is three groups of those atoms as a total

mr Goodwill [35]3 years ago

7 0

12 total atoms of nitrogen

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The archerfish is a type of fish well known for its ability to catch resting insects by spitting a jet of water at them. This sp

Delvig [45]

Answer:

Explanation:

Here is the full question and answer,

The archerfish is a type of fish well known for its ability to catch resting insects by spitting a jet of water at them. This spitting ability is enabled by the presence of a groove in the roof of the mouth of the archerfish. The groove forms a long, narrow tube when the fish places its tongue against it and propels drops of water along the tube by compressing its gill covers.

When an archerfish is hunting, its body shape allows it to swim very close to the water surface and look upward without creating a disturbance. The fish can then bring the tip of its mouth close to the surface and shoot the drops of water at the insects resting on overhead vegetation or floating on the water surface.

Part A: At what speed v should an archerfish spit the water to shoot down a floating insect located at a distance 0.800 m from the fish? Assume that the fish is located very close to the surface of the pond and spits the water at an angle 60 degrees above the water surface.

Part B: Now assume that the insect, instead of floating on the surface, is resting on a leaf above the water surface at a horizontal distance 0.600 m away from the fish. The archerfish successfully shoots down the resting insect by spitting water drops at the same angle 60 degrees above the surface and with the same initial speed v as before. At what height h above the surface was the insect?

Answer

A.) The path of a projectile is horizontal and symmetrical ground. The time is taken to reach maximum height, the total time that the particle is in flight will be double that amount.

Calculate the speed of the archer fish.

The time of the flight of spitted water is,

$t = \frac{{2v\sin \theta }}{g}$

Substitute $9.8{\rm{ m}} \cdot {{\rm{s}}^{ - 2}}$ for g and $60^\circ$ for $\theta$ in above equation.

$t = \frac{{2v\sin 60^\circ }}{{9.8{\rm{ m}} \cdot {{\rm{s}}^{ - 2}}}}\\\\ = \left( {0.1767\;v} \right){{\rm{m}}^{ - 1}} \cdot {{\rm{s}}^2}\\$

Spitted water will travel $0.80{\rm{ m}}$ horizontally.

Displacement of water in this time period is

$x = vt\cos \theta$

Substitute $\left( {0.1767\;v} \right){{\rm{m}}^{ - 1}} \cdot {{\rm{s}}^2}$ for $t\rm 60^\circ[tex] for [tex]\theta$ and $0.80{\rm{ m}}$ for x in above equation.

$\\0.80{\rm{ m}} = v\left( {0.1767\;v} \right){{\rm{m}}^{ - 1}} \cdot {{\rm{s}}^2}\left( {\cos 60^\circ } \right)\\\\0.80{\rm{ m}} = {v^2}\left( {0.1767{\rm{ }}} \right)\frac{1}{2}{{\rm{m}}^{ - 1}} \cdot {{\rm{s}}^2}\\\\v = \sqrt {\frac{{2\left( {0.80{\rm{ m}}} \right)}}{{0.1767\;{{\rm{m}}^{ - 1}} \cdot {{\rm{s}}^2}}}} \\\\ = 3.01{\rm{ m}} \cdot {{\rm{s}}^{ - 1}}\\$

B.) There are two component of velocity vertical and horizontal. Calculate vertical velocity and horizontal velocity when the angle is given than calculate the time of flight when the horizontal distance is given. Value of the horizontal distance, angle and velocity are given. Use the kinematic equation to solve the height of insect above the surface.

Calculate the height of insect above the surface.

Vertical component of the velocity is,

${v_v} = v\sin \theta$

Substitute $3.01\;{\rm{m}} \cdot {{\rm{s}}^{ - 1}}$ for v and $60^\circ$ for $\theta$ in above equation.

$\\{v_v} = \left( {3.01\;{\rm{m}} \cdot {{\rm{s}}^{ - 1}}} \right)\sin 60^\circ \\\\ = 2.6067{\rm{ m}} \cdot {{\rm{s}}^{ - 1}}\\$

Horizontal component of the velocity is,

${v_h} = v\cos \theta$

Substitute $3.01\;{\rm{m}} \cdot {{\rm{s}}^{ - 1}}$ for v and $60^\circ$ for $\theta$ in above equation.

$\\{v_h} = \left( {3.01\;{\rm{m}} \cdot {{\rm{s}}^{ - 1}}} \right)\cos 60^\circ \\\\ = 1.505{\rm{ m}} \cdot {{\rm{s}}^{ - 1}}\\$

When horizontal $({0.60\;{\rm{m}}}$ distance away from the fish.

The time of flight for distance (d) is ,

$t = \frac{d}{{{v_h}}}$

Substitute $0.60\;{\rm{m}}$ for d and $1.505{\rm{ m}} \cdot {{\rm{s}}^{ - 1}}$ for ${v_h}$ in equation $t = \frac{d}{{{v_h}}}$

$\\t = \frac{{0.60\;{\rm{m}}}}{{1.505{\rm{ m}} \cdot {{\rm{s}}^{ - 1}}}}\\\\ = 0.3987{\rm{ s}}\\$

Distance of the insect above the surface is,

$s = {v_v}t + \frac{1}{2}g{t^2}$

Substitute $2.6067{\rm{ m}} \cdot {{\rm{s}}^{ - 1}}$ for ${v_v}$ and $0.3987{\rm{ s}}$ for t and $- 9.8{\rm{ m}} \cdot {{\rm{s}}^{ - 2}}$ for g in above equation.

$\\s = \left( {2.6067{\rm{ m}} \cdot {{\rm{s}}^{ - 1}}} \right)\left( {0.3987{\rm{ s}}} \right) + \frac{1}{2}\left( { - 9.8{\rm{ m}} \cdot {{\rm{s}}^{ - 2}}} \right){\left( {0.3987{\rm{ s}}} \right)^2}\\\\ = 0.260{\rm{ m}}\\$

7 0

3 years ago

What is the metric unit for length??

blondinia [14]

Metric unit of lenght is meter (m.)

4 0

4 years ago

No matter what values of m and k you used for the spring, what is the ratio of the period to k m.

Leto [7]

The relationship between the period of an oscillating spring and the attached mass determines the ratio of the period to $\sqrt{\dfrac{m}{k} }$ .

Response:

The ratio of the period to $\sqrt{\dfrac{m}{k} }$ is always approximately 2·π : 1

<h3>How is the value of the ratio of the period to $\sqrt{\dfrac{m}{k} }$ calculated?</h3>

Given:

The relationship between the period, T, the spring constant k, and the

mass attached to the spring m is presented as follows;

$T = \mathbf{2 \cdot \pi \cdot \sqrt{\dfrac{m}{k} }}$

Therefore, the fraction of of the period to $\sqrt{\dfrac{m}{k} }$ , is given as follows;

$\mathbf{\dfrac{T}{ \sqrt{\dfrac{m}{k} }}} = 2 \cdot \pi$

2·π ≈ 6.23

Therefore;

$T :{ \sqrt{\dfrac{m}{k} }} = 2 \cdot \pi : 1$

Which gives;

The ratio of the period to $\sqrt{\dfrac{m}{k} }$ is always approximately 2·π : 1

Learn more about the oscillations in spring here:

brainly.com/question/14510622

7 0

3 years ago

Two sites are being considered for wind power generation. In the first site, the wind blows steadily at 7 m/s for 3000 hours per

slavikrds [6]

Answer:

E.year₂ > E.year₁ (Second site is better)

Explanation:

Given data

$V_{1}=7 m/s\\Time_{1}=3000 hours/year\\V_{2}=10m/s\\Time_{2}=1500hours/year$

The power generation is the time rate of kinetic energy which can be calculated as:

Power=ΔKE=m×V²/2

Regarding that m ∝ V.Then

Power ∝ V³ ⇒ Power=constant×V³

Since ρa is constant for both sides and Area is the same as same wind turbine is used

For First site

$Power_{1}=const.V^3\\Power_{1}=const.(7m/s)^3\\Power_{1}=const.343Watt\\$

For second site

$Power_{2}=const.V_{2}^3\\Power_{2}=const.(10m/s)^3\\Power_{2}=const.1000W$

Calculating energy generation per year for each of two sites

E.year=Power×Operation time per year

For First site

E.year₁=Power₁×Operation time₁ per year

$E_{year1}=const.*343W*3000\\E_{year1}=const.1029000(W.hour/year)$

For Second site

E.year₂=Power₂×Operation time₂ per year

$E_{year2}=const.*1000W*1500\\E_{year2}=const.1500000(W.hour/year)$

E.year₂ > E.year₁ (Second site is better)

3 0

3 years ago

Read 2 more answers

Plz help........................

hoa [83]

Answer:

The correct wording is

Pressure increases with the depth of the fluid.
A plane's engines produce thrust to push the plane forward.
A fluid can be a liquid or a gas.
A hydraulic device uses Pascal's principle to lift or move objects.
lift is the upward force exerted on objects by fluids.

Explanation:

1. As you go deeper into a fluid, there is more of it on top of you; therefore, the pressure excreted on you is greater.

2. A plane's engines pushes the air in opposite direction, which according to newton's third law, produces necessary force to move the plane forward.

3. A fluid has no fixed shape, and it deforms under the influence of external forces applied—liquid and gases fit into this definition.

4. Pascal's principle says that pressure applied on one region of the fluid must equal pressure transmitted to another region of the same fluid. This principle is used in a hydraulic device to exert forces on fluids to lift objects that would otherwise be difficult to move.

5. By definition, the upward force exerted by the fluids on objects is the lift.

7 0

3 years ago