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Pavel [41]
2 years ago
15

Which of the following energy transformations occurs when you eat a hamburger?

Physics
2 answers:
OLga [1]2 years ago
6 0

<u><em>Option (A) is correct. The chemical energy of the hamburger gets converted into the mechanical energy and makes the body to move.</em></u>

Explanation:

The law of conservation of energy states that the energy can neither be created nor be destroyed. It can only be converted from one form to the another using the suitable means as per the requirements.

The human body also does not generate any type of energy. It rather makes use of the energy obtained from the food and utilizes it to perform the various tasks required.

The energy stored in the food is in the form of the chemical energy of the bonds presents in the food molecules. The human body consumes the food and uses the energy from the food to convert it to mechanical energy and makes the body move and do several mechanical works and movements.

There is some loss of energy in the conversion in the human body in the form of heat and sweat etc. but this chemical energy from food is the only source of energy that is further converted into different forms by different organs as per the requirements.

Thus, <u><em>Option (A) is correct. The chemical energy of the hamburger gets converted into the mechanical energy and makes the body to move.</em></u>

<u><em></em></u>

Learn More:

1. what type of mirror do dentists use brainly.com/question/997618

2. What is the voume of drop of acetone brainly.com/question/4593217

3. Determine the parameters of the transverse wave using wave equation brainly.com/question/8904200

Answer Details:

Grade: High School

Subject: Physics

Chapter: Energy conversion

Keywords:

energy, transformation, conversion, hamburger, food, chemical, molecules, mechanical, body, move, perform, organs, digestion.

Fofino [41]2 years ago
4 0
<h2>Answer:</h2>

<u>The correct answer is </u><u>(A) The chemical energy in the food is converted to mechanical energy to give the body energy to move. </u>

<h2>Explanation:</h2>

The chemical energy in food can be converted to another form of chemical energy when it is stored as glucose or fat. The chemical energy in our food can also be converted to mechanical energy in the form of muscle movement and it provides us energy to travel and move from one place to another pace. The entire energy is not converted to mechanical though, it is also converted into heat energy.

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a_{\theta}=(ru''+2r'u')\\a_{\theta}=(2.1932\times 4+2\times 4.3864 \times 2)\\a_{\theta}=26.32 m/s\\

The transverse component of acceleration is 26.32 m/s^2

The radial component is given as

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Answer:

1. 12 V

2a. R₁ = 4 Ω

2b. V₁ = 4 V

3a. A = 1.5 A

3b. R₂ = 4 Ω

4. Diagram is not complete

Explanation:

1. Determination of V

Current (I) = 2 A

Resistor (R) = 6 Ω

Voltage (V) =?

V = IR

V = 2 × 6

V = 12 V

2. We'll begin by calculating the equivalent resistance. This can be obtained as follow:

Voltage (V) = 12 V

Current (I) = 1 A

Equivalent resistance (R) =?

V = IR

12 = 1 × R

R = 12 Ω

a. Determination of R₁

Equivalent resistance (R) = 12 Ω

Resistor 2 (R₂) = 8 Ω

Resistor 1 (R₁) =?

R = R₁ + R₂ (series arrangement)

12 = R₁ + 8

Collect like terms

12 – 8 =

4 = R₁

R₁ = 4 Ω

b. Determination of V₁

Current (I) = 1 A

Resistor 1 (R₁) = 4 Ω

Voltage 1 (V₁) =?

V₁ = IR₁

V₁ = 1 × 4

V₁ = 4 V

3a. Determination of the current.

Since the connections are in series arrangement, the same current will flow through each resistor. Thus, the ammeter reading can be obtained as follow:

Resistor 1 (R₁) = 4 Ω

Voltage 1 (V₁) = 6 V

Current (I) =?

V₁ = IR₁

6 = 4 × I

Divide both side by 4

I = 6 / 4

I = 1.5 A

Thus, the ammeter (A) reading is 1.5 A

b. Determination of R₂

We'll begin by calculating the voltage cross R₂. This can be obtained as follow:

Total voltage (V) = 12 V

Voltage 1 (V₁) = 6 V

Voltage 2 (V₂) =?

V = V₁ + V₂ (series arrangement)

12 = 6 + V₂

Collect like terms

12 – 6 = V₂

6 = V₂

V₂ = 6 V

Finally, we shall determine R₂. This can be obtained as follow:

Voltage 2 (V₂) = 6 V

Current (I) = 1.5 A

Resistor 2 (R₂) =?

V₂ = IR₂

6 = 1.5 × R₂

Divide both side by 1.5

R₂ = 6 / 1.5

R₂ = 4 Ω

4. The diagram is not complete

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