The ball's velocity will be represented by the derivative of its distance function:

Now find the times

for which this is equal to 30, i.e. solve

This has two solutions,

, but only one is positive and falls in the interval
![[0,3]](https://tex.z-dn.net/?f=%5B0%2C3%5D)
. So the velocity reaches 30 cm/s when

.
Answer:
y=mx+b
y=-4x +12 is your equation
m= yo
your slope
Step-by-step explanation:
The answer to this is 36.
Th one on the left I wanna say x=16 and the right is x=10
Answer:
LCM = 20, GCF = 9
Step-by-step explanation: