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10 months ago

The length and width of a rectangle are consecutive integers. The perimeter of the

Mathematics

1 answer:

Hunter-Best [27]10 months ago

5 0

The length of the rectangle is 9 feet and the width of the rectangle is 10 feet.

<h3>What is the Perimeter of a Rectangle?</h3>

The sum of a rectangle's boundary lengths on all sides is known as its perimeter. A rectangle's perimeter is a linear measurement that can be expressed in meters, feet, inches, or yards. Let's first comprehend the two fundamental characteristics of a rectangle.

A rectangle has four 90° angles.
The lengths of a rectangle's diagonals are equal.

Let the length of the rectangle be x feet

Then, the width of the rectangle will be x+1feet

We know that the perimeter of a rectangle is given by

P= 2(l+w)

Here

P= perimeter of a rectangle

l=length of the rectangle

w= width of the rectangle

Put l=x, w= x+1 and P= 38 in the perimeter formula

38 = 2(x+x+1)

Divide both sides by 2

19= x+x+1

19= 2x+1

Subtract 1 from both sides

18=2x

Divide both sides by 2

x=9 feet

This is the length of the rectangle.

Now, the width x+1 of the rectangle will be

9+1 = 10 feet

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Item 8

ludmilkaskok [199]

So, I didn't quite understand your question clearly, but I'll try my best to answer it.

So, the first question is quite simple: Did the runner have a % decrease in his time or an increase.
Well, 7:45 is minor than 5:51. So, his time decreased.

2nd question:
The percent of change. Well, first things first 7:45 has 2 different units, wich are minutes and seconds, I suppose. Same goes for 5:51.
So let's put everything in seconds. multiply both the 7 and 5 for 60(for every minute has 60 seconds.)

That means:
7*60= 420+45 = 465.
5*60=300+51=351.

Now, let's do the math itself:
465 -> 100%
351 -> x%
Is equal to about 75,5%
How much did it decrease then?
(75,5-100)%= 24,5%, approximately

8 0

3 years ago

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2

boyakko [2]

<u>Given</u>:

The quadratic equation is $x^{2}=-5 x-3$

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

$x^{2}+5 x+3=0$

The solution of the equation can be determined using quadratic formula.

Thus, we get;

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}$

$x=\frac{-5 \pm \sqrt{25-12}}{2 }$

$x=\frac{-5 \pm \sqrt{13}}{2 }$

Thus, the two roots of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

Hence, the solutions of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

6 0

3 years ago

Read 2 more answers

people with severe hearing loss given a sentence and word recognition test six months after they got implants in their ears the

kirza4 [7]

That would be .82 as 82% is 82/100 so that makes the answer .82

8 0

2 years ago

Does anyone know what the first question is ?

icang [17]

Answer is negative two

3 0

3 years ago

Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = ln(x2 + 3x + 4), [−2, 2]

vivado [14]

The vertex (minimum) of the quadratic ax² +bx +c is located at x=-b/(2a). This means the minimum value of f(x) will be found at x = -3/(2*1) = -1.5.

Since the vertex of the quadratic is less than 0, the maximum value of the quadratic will be found at x=2, the end of the interval farthest from the vertex.

On the given interval, ...
the absolute minimum value of f is f(-1.5) = ln(1.75) ≈ 0.559616
the absolute maximum value of f is f(2) = ln(14) ≈ 2.639057

4 0

2 years ago