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Ksenya-84 [330]
4 years ago
5

I can't seem to solve this. My rectangular soccer field site has a length equal to twice its width. Find its area in terms of it

s length x.
Mathematics
1 answer:
Sonja [21]4 years ago
5 0
Okay so they've given,
x = length
A.T.Q, 2(width)=length
2(width)= x
width = x/2
w.k.t,
Area of rectangle = (l)(b)
= (x)(x/2)
= x*2/2
I hope I was helpful
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Please giving 20 points!!!
defon

Answer:

we choose f(x) = π cos(πx)

Step-by-step explanation:

Given the information:

  • f(0) = 0
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Let analyse all possible answers;

1/ f(x) = -2 sec(x)

when x= 0 we have: f(0) = -2 sec(0) = -2\frac{1}{cos(o)} = -2 wrong

2. f(x) = 7sin(x/4 - 1/29)

when x= 0 we have: f(0) =7sin(0/4 - 1/29) = 7sin(-1/29) = -0.00421 wrong

3. (x) = π cos(πx)

when x= 0 we have: f(0) = πcos(π0) = cos(0) = π0 = 0

when x= 2 we have: f(2) = πcos(π2) = πcos(0) = π

True

4. f(x) = 2π cos(x - π/2)

when x= 0 we have: f(0) = 2π cos(0 - π/2) = 2π cos(-π/2) = 0

when x= 2 we have: f(2) =2π cos(2 - π/2) = 2π0.034 = 0.0697π Wrong

So we choose f(x) = π cos(πx)

4 0
4 years ago
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3 years ago
12.20h - 7.15 = 90.45
zhannawk [14.2K]

Answer:

H=8

Step-by-step explanation:

12.2H-7.15=90.45

12.2H=90.45+7.15

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Step-by-step explanation:

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