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2 years ago

HELPPPPPPPPPPPPPPPPPPPPPPP

Mathematics

1 answer:

LiRa [457]2 years ago

6 0

X = 1
y = -4
xy = (1)(-4) = -4

answer
C) -4

double check:
y - 4 = 4x + 3y = -(9-x)
-4 - 4 = 4(1) + 3(-4) = -(9 - 1)
- 8 = -8 = -8

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MAJORR HELP!

MaRussiya [10]

Answer:

900

Step-by-step explanation:

With a $6000 yearly premium and a $5000 deductible the break-even point would be 300 surgeries per year from a sample of 1000 insured people. Over 3 years that would equate to 900 surgeries.

$6000 x 1000 = $6000000

requiring surgery : $25000 - $5000 = $20000

Therefore $600000/$20000 = 300 claims per year

And 3 years x 300 = 900 claims over 3 years.

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2 years ago

Can you tell my friend this is right so he can stop saying it is wrong

Natasha2012 [34]

Your graph is correct.
You start with point (0, 40). On day 0, you have 40 T-shirts.
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2 years ago

Which of the following is the best answer to 4/5 minus 2/3

ella [17]

Answer:

2/15

Step-by-step explanation:

4/5-2/3 = 12/15-10/15 = 2/15

So 2/15 is your answer

6 0

2 years ago

Read 2 more answers

Tara standing 20 feet from a tree and the angle of elevation is 72°. About how tall is the tree?

Zinaida [17]

Answer:

Approx 61.554 feet

Step-by-step explanation:

Since we are dealing with the opposite and adjacent sides, we will use tangent as our ratio.

Since the angle of elevation is 72 degrees, the left side of our equation is $tan(72)$ .

The right side of the equation is opposite over adjacent.

$x/20$

Set these equal to each other.

$tan(72) = x/20$

Simplify.

$20 tan(72)=x$

$20(3.078) = x$

x is approximately 61.554.

4 0

2 years ago

Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to

ra1l [238]

Answer:

The confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

The sample size is n = 41

For a 95% confidence the level of significance is $\alpha = [100 - 95]\% = 0.05$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }= 1.96$

For a 90% confidence the level of significance is $\alpha = [100 - 90]\% = 0.10$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }= 1.645$

So we see with decreasing confidence level the critical value decrease

Now the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{n} }$

given that other values are constant and only $Z_{\frac{\alpha }{2} }$ is varying we have that

$E\ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Hence for reducing confidence level the margin of error will be reducing

The confidence interval is mathematically represented as

$\= x - E < \mu < \= x + E$

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower

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2 years ago