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3 years ago

Help ASAP with the question.

Mathematics

2 answers:

givi [52]3 years ago

6 0

The answer is 5 x 10^10

Hope this helped! :)

Darya [45]3 years ago

6 0

Subtraction in scientific notation is pretty similar to adding, first because the exponents are the same, you can subtract 4 from 9 and =get 5 and because the exponents need to be the same, you just keep 10^10

Your final answer is 5x10^10

Hope this helped!

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3 years ago

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What is the mean absolute deviation of the data set {30,33,36,34,52}?

Georgia [21]

Answer:

Step-by-step explanation:

I took the test and got 100%

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3 years ago

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I have been asking for assistance for an hour and a half now, I will greaty appreciate anyone that can help with this..Find the

blagie [28]

Answer:

1st graph: m = -1/2. (m is the slope)

2nd graph: m = 3/2.

3rd graph: Midpoint = (1/2, 1/2)

Step-by-step explanation:

1st graph:

Find the slope by looking for two points on the line. Use the formula $m = \frac{y_{2}-y_{1} }{x_{2}-x_{1}}$

We can derive the points (-3, 0) and (1, -2). Plug these into the equation above.

$m= \frac{-2-0}{1-(-3)}$

Simplify this, giving you: m = -1/2.

2nd graph:

Use the same formula as stated above. From this graph, you can plug in the points (-1, 1) and (1, 4)

$m = \frac{4-1}{1-(-1)}$

Simplifying gets you: m = 3/2.

3rd graph:

To find the midpoint, use the formula: $(\frac{x_{1}+x_{2} }{2} , \frac{y_{1} +y_{2} }{2} )$

Plug in the end-points of the graph, or (-3, 2) and (4, -1).

You get:

$(\frac{-3+4}{2}, \frac{2-1}{2})$

Simplify:

Midpoint = (1/2, 1/2)

3 0

3 years ago

The top of an off shore oil rig has an elevation of 199.2 m and its base has an elevation of -9.6 m and observation deck is loca

matrenka [14]

Answer: 57.6m

Step-by-step explanation:

That's a lot of words that questions usually use to try to trip us up but not this time so lets pull all relevant information

199.2m= top of off shore oil rig

-9.6 m is the base of the rig

observation deck is 1/6 of the total height

helly pad is 22.8m above the observation deck

First lets try to find the total height of the rig. We can do this by adding the absolute value of the top and base of the oil rig. So 199.2 + 9.6 = 208.8m

So the total height is 208.8m now lets find the observation deck. We know the observaition is 1/6 of the total height which is 208.8m right so lets multiply. 1/6*208.8m= 34.8m

Now we know the observation deck is 34.8m high. Finally we can find the helly pad which is 22.8 m above the observation deck.

Since the observation deck is 34.8m and the helly pad is 22.8 above observation deck (34.8m) all we have to do is add so 22.8+34.8= 57.6m

So we know the total height is 208.8m

The observation deck is 34.8m

And the helly pad is 57.6m

7 0

3 years ago

Please dont ignore, Need help!!! Use the law of sines/cosines to find..

Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

$\sin{A} = \sin{103\textdegree{}}$ ,
The opposite side of angle A $a = BC = 26$ ,
The angle C is to be found, and
The length of the side opposite to angle C $c = AB = 6$ .

$\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}$ .

$\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}$ .

$\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}$ .

Note that the inverse sine function here $\sin^{-1}()$ is also known as arcsin.

By the law of cosine,

$c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C}$ ,

where

$a$ , $b$ , and $c$ are the lengths of sides of triangle ABC, and
$\cos{C}$ is the cosine of angle C.

For triangle ABC:

$b = 21$ ,
$c = 30$ ,
The length of $a$ (segment BC) is to be found, and
The cosine of angle A is $\cos{123\textdegree}$ .

Therefore, replace C in the equation with A, and the law of cosine will become:

$a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}$ .

$\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}$ .

For triangle ABC:

$a = 14$ ,
$b = 9$ ,
$c = 6$ , and
Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

$b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}$ .

$\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}$ .

$\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree$ .

For triangle DEF:

The length of segment DF is to be found,
The length of segment EF is 9,
The sine of angle E is $\sin{64\textdegree}}$ , and
The sine of angle D is $\sin{39\textdegree}$ .

Apply the law of sine:

$\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}$

$\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9$ .

7 0

3 years ago