It is false that the midpoint is in quadrant IV
<h3>How to determine the midpoint location?</h3>
The endpoints are given as:
S (1,4) and T (5,2
The midpoint is
(x, y) = 0.5 *(x1 + x2, y1 + y2)
So, we have:
(x, y) = 0.5 *(1 + 5, 4 + 2)
Evaluate the expression
(x, y) = (3, 3)
The point (3, 3) is located in the first quadrant
Hence, it is false that the midpoint is in quadrant IV
Read more about quadrants at:
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Answer: B
Step-by-step explanation:
YOU MINUS 4 -4 WHICH IS -8 SO ITS B
Answer:
Step 1: Remove parentheses by multiplying factors.
= (x * x) + (1 * x) + (2 * x) + (2 * 1)
Step 2: Combine like terms by adding coefficients.
(x * x) = x2
(1 * x) = 1x
(2* x) = 2x
Step 3: Combine the constants.
(2 * 1) = 2
Step 4: Therefore, Simplifying Algebraic Expression is solved as
= x2 + 3x + 2.
Answer: 2014
Step-by-step explanation:
LED: -25x + 6y = 20
CFL: 15x + 2y = 322
we need to find which year it was the same to know where LED lighting surpassed CFL lighting
-25x + 6y = 20
15x + 2y = 322 (-3)
-25x + 6y = 20
<u>-45x - 6y = -966 </u>
-70x = -946
x = 13.51
The nearest year would be 14 which is 2014
Answer:
Describe in detail how you would create a number line with the following points: 3, 2.25, the opposite of 4, and – (–1fraction of one-half). Please be sure to describe on which tick marks each point is plotted and how many tick marks are between each integer. It may help for you to draw this number line by hand on a sheet of paper first.
Step-by-step explanation:
