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Yuliya22 [10]
4 years ago
8

Hurry plz!!!

Physics
1 answer:
lora16 [44]4 years ago
4 0
The statement is true
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Hii I need help ASAP with this physics question
Readme [11.4K]

Between the top of the first and the top of the second loop, the coaster has lost potential energy = mgh, where h = 22.2 - 15 = 7.2m

This energy would have converted to Kinetic. Write out an equation and the masses will cancel out. Does that hint help you to find the solution? If not, I will give you another hint.

4 0
3 years ago
A spacecraft is fueled using hydrazine (N2H4; molecular weight of 32 grams per mole [g/mol]) and carries 1640 kilograms [kg] of
Sauron [17]

Answer:

The value is t = 689.029 \  hours

Explanation:

From the question we are told that

The molar mass of hydrazine is Z =  32 g/mol = \frac{32}{1000} = 0.032 \  kg/mol

The initial temperature is T_i  =  -186 ^o F = (-186-32) *\frac{5}{9} +273.15 = 152\ K

The final temperature is T_f  =  78 ^o F = (78-32) *\frac{5}{9} +273.15 = 298.7 \ K

The specific heat capacity is c_h  =  0.099 [kJ/(mol K)] = 0.099 *10^3 J/(mol/K)

The power available is P = 300 \ W

The mass of the fuel is m =   1640 \  kg

Generally the number of moles of hydrazine present is

n  =  \frac{m}{Z}

=> n  =  \frac{1640}{= 0.032}

=> n  =  51250 \ mol

Generally the quantity of heat energy needed is mathematically represented as

Q =  n * c_h * (T_f -T_i)

=> Q =  51250  * 0.099 *10^3  * (298.7 - 152)

=> Q =  7.441516913 * 10^{8} \  J

Generally the time taken is mathematically represented as

t =  \frac{Q}{P}

=> t =  \frac{7.441516913 * 10^{8} }{300}

=> t = 2480505.6377 s

Converting to hours

t = \frac{2480505.6377}{3600}

=> t = 689.029 \  hours

6 0
3 years ago
Fifteen identical particles have various speeds: one has a speed of 2.00 m/s, two have speeds of 3.00 m/s, three have speeds of
Evgesh-ka [11]

Answer:

a)  V=7.5m/s

b) rms=8.4m/s

c) Generally the most probable speed is 8m/s as it the most posses by particles being the average

Explanation:

From the question we are told that:

Sample size N=15

  Speed 1 v_1=2m/s\\\\Speed 2 v_2=3m/s\\\\Speed 3 v_2=5m/s\\\\Speed 4 v_4=8m/s\\\\Speed 3 v_5=9m/s\\\\Speed 2 v_6=15m/s\\\\

Generally the equation for Average speed is mathematically given by

 V_{avg}=\frac{\sum(nv)}{N}

Therefore

 V_{avg}=\frac{(2+2(3)+3(5)+4(8)+3(9)+2(15))}{15}

 V=7.5m/s

b)

Generally the equation for RMS speed of the particle is mathematically given by

  rms=\sqrt{\frac{\sum(nv^2)}{N}}

  rms=\sqrt{\frac{2^2+2(3)^2+3(5)^2+4(8)^2+3(9)^2+2(15)^2}{15}}

  rms=\sqrt{69.73}

  rms=8.4m/s

c

Generally the most probable speed is 8m/s as it the most posses by particles being the average

4 0
3 years ago
HELP!!! I MIGHT FAIL THE 6th GRADE IF I DON'T GET HELP!!!! The southern United States experiences periodic occurrences of severe
VikaD [51]

Answer:

La Niña, because the jet stream is displaced northwards

Explanation:

La Nina is known to be a cool phase that affects the average ocean temperature. During this period the surface wind becomes stronger and there is lesser rainfall over the areas of the central tropical Pacific to which the Southern United States belongs.

Hence, when the southern United States experiences periodic occurrences of severe cold and drought conditions, the weather phenomenon most likely causes this and why is "La Niña, because the jet stream is displaced northwards."

3 0
3 years ago
A 2-kg cart, traveling on a horizontal air track with a speed of 3m/s, collides with a stationary 4-kg cart. The carts stick tog
ladessa [460]

Answer:

The impulse exerted by one cart on the other has a magnitude of 4 N.s.

Explanation:

Given;

mass of the first cart, m₁ = 2 kg

initial speed of the first car, u₁ = 3 m/s

mass of the second cart, m₂ = 4 kg

initial speed of the second cart, u₂ = 0

Let the final speed of both carts = v, since they stick together after collision.

Apply the principle of conservation of momentum to determine v

m₁u₁ + m₂u₂ = v(m₁ + m₂)

2 x 3 + 0 = v(2 + 4)

6 = 6v

v = 1 m/s

Impulse is given by;

I = ft = mΔv = m(

The impulse exerted by the first cart on the second cart is given;

I = 2 (3 -1 )

I = 4 N.s

The impulse exerted by the second cart on the first cart is given;

I = 4(0-1)

I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).

Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.

8 0
4 years ago
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