1) F=q[vB], where q -> charge, v-> velocity, B-> magnetic field. [ , ] -> cross product.
2) f=q*v*B*sin(11°) {1}
3) 1.6f=q*v*B*sin(alpha) {2}
4) {2} / {1} -> 1.6=sin(alpha)/sin(11°) or sin(alpha)=1.6*sin(11°) --> alpha=arcsin (1.6*sin(11°))
So, alpha=17.7°=18°
Answer:
1. You push on the ball and the ball pushes on your hand
.
2. The ball hits the ground and the ground pushes back on the ball
.
3. You walk on the ground with your feet and the ground pushes back on you.
Explanation:
A no . answer is velocity of the object. B no.answer is Acceleration of the object. C no.answer is straight line shape and a velocity graph with a horizontal shape D no.answer is curved shape and a velocity graph with a straight shape.
Answer:
Approximately 
upwards (assuming that 
.)
Explanation:
External forces on this astronaut:
- Weight (gravitational attraction) from the earth (downwards,) and
- Normal force from the floor (upwards.)
Let 
denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:
.
Let 
denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be 
.
Let 
denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be 
.
Rearrange to obtain an expression for the magnitude of the normal force on this astronaut:
.
