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Xelga [282]
2 years ago
6

How can isotopes of a given element be identified?​

Physics
1 answer:
marin [14]2 years ago
6 0

Answer: All isotopes of a given element have the same number of protons but different numbers of neutrons in each atom. ... Each atomic number identifies a specific element, but not the isotope; an atom of a given element may have a wide range in its number of neutrons.

Explanation: Hopefully this helps. Have a great day.

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Concept Simulation 2.3 offers a useful review of the concepts central to this problem. An astronaut on a distant planet wants to
Alexandra [31]

Answer:

1.40 m/s^2

Explanation:

Given data

Velocity= 17.4 m/s

time= 12.4 seconds

We want to find the acceleration of the rock

We know that

acceleration = velocity/time

Substitute

acceleration= 17.4/12.4

acceleration=1.40 m/s^2

Hence the acceleration is 1.40 m/s^2

7 0
2 years ago
Why is honesty especially important in a scientist when the results of an experiment go against predictions❓❔
kramer
Because other scientists and science in general rely on their collegues' research which in turn allows development of our knowledge on the given subject. The more dont-to-earth reason may be safety. If someone performs an experiment without knowledge of its true results it might result in some danger to the safety of those perforning it without knowledge of all the risks.
8 0
3 years ago
A 10.0 g bullet moving at 300m/s is fired into a 1.00 kg block at rest. The bullet emerges (the bullet does not get embedded in
chubhunter [2.5K]

Answer:

v' = 1.5 m/s

Explanation:

given,

mass of the bullet, m = 10 g

initial speed of the bullet, v = 300 m/s

final speed of the bullet after collision, v' = 300/2 = 150 m/s

Mass of the block, M = 1 Kg

initial speed of the block, u = 0 m/s

velocity of the block after collision, u' = ?

using conservation of momentum

 m v + Mu = m v' + M u'

 0.01 x 300 + 0 = 0.01 x 150 + 1 x v'

v' = 0.01 x 150

v' = 1.5 m/s

Speed of the block after collision is equal to v' = 1.5 m/s

5 0
2 years ago
A bike and rider together have a mass of 60 kg. If the bike and rider have an acceleration of 2.0 m/s^2, what is the force on th
Mice21 [21]

The net force on the bike and the rider is 120 N

Explanation:

We can solve this problem by applying Newton's second law of motion, which states that:

F = ma

where

F is the net force exerted on an object

m is the mass of the object

a is its acceleration

For the bike and the rider in this problem, we have

m = 60 kg is their combined mass

a=2.0 m/s^2 is their acceleration

Therefore, the net force on them is

F=(60)(2.0)=120 N

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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3 years ago
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