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noname [10]
3 years ago
5

A penny is dropped from the 82nd Floor Observatory of the Empire State Building. The penny will fall for 8.1s before hitting the

ground. 1. How far does the penny fall? 2. How fast is the penny going when it hits the ground?
Physics
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

<em>vf=79.38 m/s</em>

<em>y= 321.5 m</em>

Explanation:

<u>Free Fall Motion</u>

A free-falling object falls under the exclusive influence of gravity. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is g = 9.8 m/s^2.

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The distance traveled by a dropped object is:

\displaystyle y=\frac{gt^2}{2}

1.

The penny will fall for t=8.1 s before hitting the ground, thus the height from which it was dropped is:

\displaystyle y=\frac{9.8\cdot 8.1^2}{2}

y= 321.5 m

2.

The final velocity is:

vf=9.8\cdot 8.1

vf=79.38 m/s

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Complete question:

A 45-mH ideal inductor is connected in series with a 60-Ω resistor through an ideal 15-V DC power supply and an open switch. If the switch is closed at time t = 0 s, what is the current 7.0 ms later?

Answer:

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Explanation:

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Ideal voltage supply, V = 15-V

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I₀ = V/R

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T = 7.5 x 10⁻⁴ s

Change in current with respect to time, is given as;

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The inductor in a radio receiver carries a current of amplitude 200 mA when a voltage of amplitude 2.4 V is across it at a frequ
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Answer:

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Explanation:

Given;

amplitude current, I₀ = 200 mA = 0.2 A

amplitude voltage, V₀ = 2.4 V

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X_l = \frac{V_o}{I_o} \\\\X_l = \frac{2.4}{0.2} \\\\X_l =12 \ ohms

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