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Maurinko [17]
3 years ago
15

An MRI technician moves his hand from a region of very low magnetic field strength into an MRI scanner's 2.00 T field with his f

ingers pointing in the direction of the field. His wedding ring has a diameter of 2.5 cm and it takes 0.45 s to move it into the field. What average current is induced in the ring in A if its resistance is 0.0100 Ω ?
Physics
1 answer:
makkiz [27]3 years ago
7 0

Answer:

2.62 A

Explanation:

B = 2 T, Diameter = 2.5 cm , radius, r = 0.0125 m, t = 0.45 s, r = 0.01 ohm

Induced emf, e = rate of change of magnetic flux

e = A x dB / dt = 3.14 x (0.0125)^2 x 2 / 0.45

e = 0.026 V

induced current, i = e / R = 0.026 / 0.01 = 2.62 A

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A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
lidiya [134]

Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
3 years ago
Read 2 more answers
When two identical resistors are connected in series across ideal battery, total power dissipated by them is P. Now both are con
Art [367]

Answer:

4 P

Explanation:

V = IR

     when they are in series   R = 2 r

     when they are in parallel R = 1/2 r

         so current will increase by a factor of 4  when they are in parallel

              and power used will also increase by a factor of 4  to  4 P

Power = IV       when I now becomes 4 I     power becomes 4 P

4 0
2 years ago
Calculate the amount of heat (in kj) required to convert 74.6 g of water to steam at 100°c
Kryger [21]
You just need the energy of turning of water in to steam. Water is a little funny because once water gets to 100 degrees C, it stops changing in temperature whilst it all turns to steam. The amount of energy required to turn 1 gram of water into steam is 2257 Joules. We call this the latent heat of vaporisation. So to turn 74.6 grams of water to steam, you would need:

2257J/gram x 74.6g = 168,372.2 J = 168.4 kJ

(<span></span><em>latent heat of vaporisation: 2257 J/gram</em>)


7 0
3 years ago
what is the momentum of a child and a wagon if the total mass of the child and wagon is 22kg and the velocity is 1.5m/s?
antoniya [11.8K]

Answer:

33 kg m/s

Explanation:

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is the velocity of the object

In this problem, the total mass of the child and the wagon is m =22 kg, while the velocity is v = 1.5 m/s, therefore the momentum is

p=mv=(22 kg)(1.5 m/s)=33 kg m/s

7 0
3 years ago
A 45.0 kg ice skater stands at rest on the ice. A friend tosses the skater a 5.0 kg ball. The skater and the ball then move back
Allushta [10]

Answer:

u = 5 m/s

Explanation:

given,

Mass of ice skater, M = 45 Kg

initial speed = 0 m/s

mass of the ball, m = 5 Kg

velocity of skater and the ball,V = 0.5 m/s

speed of the ball = ?

using conservation of momentum

m u + M u' =( M + m ) V

initial speed of ice skater is zero

5 x u + 45 x 0 =( 45 + 5 ) V

5 u = 50 x 0.5

5 u = 25

u = 5 m/s

hence, the speed of the ball is equal to 5 m/s

0 0
3 years ago
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