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3 years ago

The amount of kinetic energy an object has depends on its.

2 answers:

7 0

<span>The amount of kinetic energy an object has depends on its "speed." Kinetic energy is energy a object has while its in motion so the key word is speed.

Hope this helps!
</span>

KiRa [710]3 years ago

4 0

Formula
KE = 1/2 m v^2

Discussion
The formula shows that the Kinetic Energy has 2 parts
m = mass
v = speed

So if you increase either the mass or the speed, you will get an increase in Kinetic Energy.

Answer
mass
speed

You might be interested in

What is the total energy q released in a single fusion reaction event for the equation given in the problem introduction? use c2

kkurt [141]

Answer:

$4.3\cdot 10^{-12} J$

Explanation:

The fusion reaction in this problem is

$4^1_1H \rightarrow ^4_2He +2e^+$

The total energy released in the fusion reaction is given by

$\Delta E = c^2 \Delta m$

where

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\Delta m$ is the mass defect, which is the mass difference between the mass of the reactants and the mass of the products

For this fusion reaction we have:

$m(^1_1H)=1.007825u$ is the mass of one nucleus of hydrogen

$m(^4_2 He)=4.002603u$ is the mass of one nucleus of helium

So the mass defect is:

$\Delta m =4m(^1_1 H)-m(^4_2 He)=4(1.007825u)-4.002603u=0.028697u$

The conversion factor between atomic mass units and kilograms is

$1u=1.66054\cdot 10^{-27}kg$

So the mass defect is

$\Delta m =(0.028697)(1.66054\cdot 10^{-27})=4.765\cdot 10^{-29}kg$

And so, the energy released is:

$\Delta E=(3.0\cdot 10^8)^2(4.765\cdot 10^{-29})=4.3\cdot 10^{-12} J$

6 0

3 years ago

When using a stream table in a classroom setting what are three factors that can be controlled?

UNO [17]

Answer:

<h3><em>These include the slope of the land, the nature of the land surface, the placement of dams, and the direction of topsoil disturbance as created by farming activities. Materials: Students should work in groups of 3 or 4, or as materials allow.</em></h3>

Explanation:

<h3><em>Hope this helps </em></h3>

3 0

2 years ago

Aleksandr-060686 [28]

Answer:

Curl up test.

Explanation:

The curl up test is done to check the strength of the abdomen muscles and the stability of the core muscles. The strength of the core muscles determines the stability of the body.

The curl up test is done to test the abdomen strength and endurance and the strength of the back muscles.

The test requires the following materials: A flat cushioned surface(clean) and a measuring strip

The measuring strip is placed on the mat under the students legs so that their fingertips are just resting on the nearest edge of the measuring strip. The feet cannot be held or rest against an object. Keeping heels in contact with the mat, the student curls up slowly, sliding their fingers across the measuring strip until the fingertips reach the other side, then curls back down until their head touches the mat. There should be 20 curl-ups per minute

8 0

3 years ago

A 75-turn coil with a diameter of 6.00 cm is placed in a constant, uniform magnetic field of 1.00 T directed perpendicular to th

kolezko [41]

Answer:

The induced emf in the coil at the t = 5s is 6.363 mV

Explanation:

Given;

number of turns = 75

diameter of the coil = 6 cm

magnetic field strength = 1 T

new magnetic field strength = 1.30 T at t = 10.0 s

$Area \ of \ coil = \frac{\pi d^2}{4} = \frac{\pi *0.06^2}{4} = 0.002828 \ m^2$

$E.M.F = \frac{NA* \delta B}{\delta t}$

Between 0 to 5 s, Induced emf is given as;

$E.M.F = \frac{75*0.002828*(B_5-1)}{5}$

Between 5 to 10 s, Induced emf is given as;

$E.M.F = \frac{75*0.002828*(1.3-B_5)}{5}$

Since the field increased at a uniform rate until it reaches 1.30 T at t = 10.0 s, the induced emf will also increase in uniform rate. And equal time interval will generate same increase in field strength.

B₅ -1 = 1.3 - B₅

2B₅ = 2.3

B₅ = 1.15 T

Thus, magnetic field at t = 5 is 1.15 T

$E.M.F = \frac{75*0.002828*(1.3-1.15)}{5} = 6.363 \ mV$

Therefore, the induced emf in the coil at the t = 5s is 6.363 mV

7 0

3 years ago

Write a program that calculates the average of n integers. the program should prompt the user to enter the value for n and then

ikadub [295]

#include<studio.h>

int main( )

{

int n;

int a,b,c,d,x,y;

int avarage;

printf("enter value of n:\n");

scanf("%d",&n);

printf("enter value of a:\n,b:\n,c:\n,d:\n,x:\n,y:\n);

scan f("%d\%d\n%d\n%d\n%d\n%d\n",&a,b,c,d,x,y);

sum=(a+b+c+d+x+y);

avarage=(sum/n);

print f("%d",avarage);

{

n=positive interger

}

else

{

printf ("n must be positive");

}

return 0;

}

8 0

3 years ago