In fact, the force Rahul exerts on Earth corresponds to the force of gravity. But Rahul's weight is, in fact, the force of gravity exerted by the Earth on Rahul, and these two forces correspond to the action-reaction pair of Newton's third law, which states that the two forces are equal.
Answer:
12552 J or 3000 calories
Explanation:
Q = m × c × ∆T
Where;
Q = amount of heat energy (J)
m = mass of water (g)
c = specific heat capacity (4.184 J/g°C)
∆T = change in temperature
For 50mL of water, there are 50g, hence, m = 50g, c = 4.184 J/g°C, initial temperature = 0°C, final temperature = 60°C.
Q = m × c × ∆T
Q = 50 × 4.184 × (60 - 0)
Q = 209.2 × 60
Q = 12552 J
Hence, the amount of heat energy used to heat the water is 12552 J or 3000 calories
<span>The answer is 6 kg the mass of the second
object. By using Inversely proportional formula it means that (14 kg) (3 m/s</span>²<span>)
= M (7 m/s</span>²<span>). Where M is the mass of the second object. For the
Newton’s second law of motion formula which is: Force = mass x acceleration, we
have:</span>
<span>F = (14 kg) (3 m/s</span>²<span>) = 42 N</span>
Therefore:
<span>42 N = M (7 m/s</span>²)
<span>M = (42 N) / (7 m/s</span>²<span>)</span>
M = 6 kg mass of the second object
formed by the process of glaciation.