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LiRa [457]
3 years ago
15

PLEASE HELP 20+ POINTS!! What is the cosine equation of the function shown?

Mathematics
1 answer:
noname [10]3 years ago
8 0

Answer:   \bold{y=7\ \cos\bigg(x-\dfrac{\pi}{4}\bigg)-4}

<u>Step-by-step explanation:</u>

y = A cos (Bx - C) + D

  • A (amplitude) = max - D
  • B = Period/2π  --->   Period is the distance from max to next max
  • C = B · Phase Shift  ---> Phase shift is distance from y-axis to max
  • D (vertical shift) = (max + min)/2

D = (max + min)/2     =     (3 - 11)/3      =  -4

A = max - D               =     3 - (-4)         = 7

Period = 9π/4 - π/4   =    8π/4            = 2π

B = Period/2π           =    2π/2π          = 1

Phase Shift = π/4 - 0 =     π/4

C = B · Phase Shift    =  1 · π/4            = π/4

Equation:

           y = 7 cos (1·x - π/4) + (-4)

               

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Answer: 70

Step-by-step explanation: The absolute value of a number is its distance from zero on the number line. Since absolute value is a distance, it is always greater than or equal to zero.

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2 years ago
Simplify the expression. (p^9)^−2
EastWind [94]
<span><span> p9/p3</span> </span>Final result :<span> p6 </span>Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "p3"   was replaced by   "p^3".  1 more similar replacement(s).

Step by step solution :<span>Step  1  :</span><span> p9 Simplify —— p3 </span>Dividing exponential expressions :

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3 years ago
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Vladimir79 [104]

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7 0
2 years ago
One speed skater starts across a frozen lake at an average speed of 8 m/s. Ten seconds later, a second speed skater starts from
Galina-37 [17]

Answer: Hello mate!

Let's define the variable t as the time, and define t = 0 as the moment when the first skater starts to move:

We know that the speed of the first skater is 8 m/s, and we need to find the position as a function of time, then we need to integrate the velocity over time

if v1(t) = 8m/s

then p1(t) = (8m/s)*t

now we also know that the second skater has a velocity of 9m/s and enters in the frozen lake at t= 10s.

then the velocity of the second skater is: v2(t) = 9m/s, and the position is:

p2(t) = (9m/s)*(t - 10s)

now we want to know how many seconds after the second skater starts are needed for the second skater to overtake the first one.

this is equivalent to see when his positions will be equal.

so p1(t) = p2(t):

(8m/s)*t = (9m/s)(t - 10s) = (9m/s)*t - 90m

(8m/s)*t - (9m/s)*t = -90m

(-1m/s)*t = 90m

t = 90m/(1m/s) = 90s

Then in t = 90 seconds, the second skater will overtake the first one, and knowing that the second skater started at t = 10 seconds; there are 80 seconds after the second skater started needed to overtake the first skater.

7 0
2 years ago
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