Please help!! Find the value of x. X=

Mathematics

2 answers:

LenaWriter [7]2 years ago

6 0

Answer:

Step-by-step explanation:

Hello,

We can write three equations thanks to Pythagoras

$AB^2+AC^2=(7+3)^2\\x^2+7^2=AB^2\\x^2+3^2=BC^2\\$

So it comes

$x^2+7^2+x^2+3^2=(7+3)^2\\\\2x^2=100-49-9=42\\\\x^2 = 42/2=21\\\\x = \sqrt{\boxed{21}}\\$

Hope this helps

vovikov84 [41]2 years ago

3 0

Answer:

x = $\sqrt{21}$

Step-by-step explanation:

Δ BCD and Δ ABD are similar thus the ratios of corresponding sides are equal, that is

$\frac{BD}{AD}$ = $\frac{CD}{BD}$ , substitute values

$\frac{x}{7}$ = $\frac{3}{x}$ ( cross- multiply )

x² = 21 ( take the square root of both sides )

x = $\sqrt{21}$

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Jane multiplies her number by three and subtracts 2.

katrin [286]

Answer:

Let the number they chose be 'x'.

Result of Jane = $3x -2$

Result of Elliot = $2x+3$

Given that,

The product of their result = 110

$or, (3x-2)(2x+3) = 110\\or, 6x^{2} +9x-4x-6 = 110\\or, 6x^{2} +5x - 6 = 110\\or, 6x^{2} +5x - 6-110 = 0\\\\or, 6x^{2} +5x - 116 = 0\\or, 6x^{2} +29x - 24x - 116 = 0\\or, x (6x +29) -4(6x+29) = 0\\or, (x-4)(6x+29) = 0\\i.e. x=4 or x=\frac{-29}{6} \\So,~ the ~number ~they~ chose~was ~either ~4 ~or ~\frac{-29}{6}$

3 0

2 years ago

PLEASE HELP ASAP

olganol [36]

From the figure, the vertices of the given triangle are
(-3,4), (1,3) and (5,5).

The given transformation is (x,y) -> (x+3, y-2).
Therefore the coordinates of the transformed triangle are
(-3+3,4-2), (1+3,3-2), (5+3,5-2) = (0,2), (4,1), (8,3)

The transformed triangle is shown in red color.