Question

Please help!! Find the value of x. X=

Answer 1

Answer:

Step-by-step explanation:

Hello,

We can write three equations thanks to Pythagoras

   $AB^2+AC^2=(7+3)^2\\x^2+7^2=AB^2\\x^2+3^2=BC^2$

So it comes

$x^2+7^2+x^2+3^2=(7+3)^2\\\\2x^2=100-49-9=42\\\\x^2 = 42/2=21\\\\x = \sqrt{\boxed{21}}$

Hope this helps

Answer 2

Answer:

x = $\sqrt{21}$

Step-by-step explanation:

Δ BCD and Δ ABD are similar thus the ratios of corresponding sides are equal, that is

$\frac{BD}{AD}$ = $\frac{CD}{BD}$ , substitute values

$\frac{x}{7}$ = $\frac{3}{x}$ ( cross- multiply )

x² = 21 ( take the square root of both sides )

x = $\sqrt{21}$