For the answer to the question above, I've used my calculator to inverse your given equation because my brain can't do that.
The answer to your question is
In radians, arcsin(sin(9π) / 7) = 0.
i hope my answer helped you.
In this problem, we need to plug in the given x values for

and find a and b.
When we plug in 1, we get:

Simplify:



We got our first statement about the values of the variables. If we find one more we can find those 2 variables.
We have another given root: 4.
Plug it in:




Now we have our second one. We can combine them:

I use elimination method which is easier here.
Multiply the top equation by -1:

Add them up:

Simplify:

Now we have a, we can plug in one of those equations to find b:



So, the answers are

and

.
To find the hypothenuse use Pythagorean theorem: 13²+5²=h²,
h=√13²+5²=13.93cm = hypothenuse.
Answer:
The seconf option
x = 0, 2, 4
y = 3,5,7
Step-by-step explanation:
plug in your x and y points into the equation and they should be the same of both sides
ex (0,3)
3 = 0 + 3
^y ^x