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ozzi
3 years ago
14

a photographer shines a camera light at a particular painting forming an angle of 50 degrees with a camera platform at the light

is 55 feet from the wall where the painting hangs how high above the platform is the painting​

Mathematics
1 answer:
umka2103 [35]3 years ago
8 0

Answer:

The painting is 42.13 feet above  the platform

Step-by-step explanation:

Refer the attached figure .

A particular painting forming an angle of 50 degrees with a camera platform .

∠ABC = 50°

We are also given that the light is 55 feet from the wall where the painting hangs

i.e. AB = 55 feet.

Now we are required to find how high above the platform is the painting​. i.e. AC

So, we will use trigonometric ratio :

sin\theta = \frac{Perpendicular}{Hypotenuse}

sin50^{circ} = \frac{AC}{AB}

sin50^{circ} = \frac{AC}{55}

0.766*55 = AC

42.13= AC

Thus the painting is 42.13 feet above  the platform

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Answer:

y=+3

Step-by-step explanation:

the equation of a line is y=mx+c

where m is the slope and c is the y-intercept.

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (0,3), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=0 and y1=3.

Also, let's call the second point you gave, (-5,3), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-5 and y2=3.

Now, just plug the numbers into the formula for m above, like this:

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m=0

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To find c, think about what your (x,y) points mean:

(0,3). When x of the line is 0, y of the line must be 3.

(-5,3). When x of the line is -5, y of the line must be 3.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=0x+c. c is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (0,3) and (-5,3).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for c for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

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(-5,3). y=mx+c or 3=0x -5+c, or solving for c: =3-(0)(-5). c=3.

See! In both cases we got the same value for c. And this completes our problem.

The equation of the line that passes through the points

(0,3) and (-5,3)  

is  

y=+3

Hope this helps :)

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