Question

a photographer shines a camera light at a particular painting forming an angle of 50 degrees with a camera platform at the light is 55 feet from the wall where the painting hangs how high above the platform is the painting​

Answer 1

Answer:

The painting is 42.13 feet above  the platform

Step-by-step explanation:

Refer the attached figure .

A particular painting forming an angle of 50 degrees with a camera platform .

∠ABC = 50°

We are also given that the light is 55 feet from the wall where the painting hangs

i.e. AB = 55 feet.

Now we are required to find how high above the platform is the painting​. i.e. AC

So, we will use trigonometric ratio :

$sin\theta = \frac{Perpendicular}{Hypotenuse}$

$sin50^{circ} = \frac{AC}{AB}$

$sin50^{circ} = \frac{AC}{55}$

$0.766*55 = AC$

$42.13= AC$

Thus the painting is 42.13 feet above  the platform