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sergeinik [125]
3 years ago
12

The mean computed from ungrouped data is a more accurate measure than the mean computed from grouped data?

Mathematics
1 answer:
Rufina [12.5K]3 years ago
4 0
It doesn’t make any difference whether or not the data is grouped, the mean is the same. So b. false.
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Plz help, I promise I will give brainliest
Vadim26 [7]

Answer:

Graph shifts five units down.

Step-by-step explanation:


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2 years ago
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A prism has total surface area of 360 m2 and volume of 60 m². If the length, width,
Karolina [17]

Answer:

480

Step-by-step explanation:

I did the test and this is what it said in the review.

3 0
3 years ago
What is the average rate of change of the function f(x)=5(2)^x from x = 1 to x = 5?
Mila [183]
Average rate of change refers to the slope of a function/equation. 
To solve this, plug in for both x values and calculate the average, or mean. 

x = 1 
f(1) = 5(2)^1 
      = 5(2) 
      = 10

x = 5 
f(5) = 5(2)^5
      = 5(32) 
      = 160

Now, you calculate the average: 
10 + 160 = 170 
Divide by 2 and you get 85.



5 0
2 years ago
Brainliest to the first CORRECT answer, Thanks
kotykmax [81]

Answer:

28 inches

Step-by-step explanation:

P = 2 (a + b) = 2 · (6 + 8) = 28

5 0
3 years ago
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
2 years ago
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