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3 years ago

Helppppppppppppppppppppppppp

Mathematics

1 answer:

VashaNatasha [74]3 years ago

7 0

First you need to find out how long she worked

7:32 to 3:43 is 8 hours and 11 minutes.

Multiply 6.75(her per hour salary) by 8 and you have $54. But you still have 11 minutes. 11 minutes is roughly 18.33% of an hour. So multiply 6.75 by 0.18 which is 1.25. Your answer is $55.24

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It costs $35 per hour to rent a boat at the lake. You also need to pay a $25 fee for safety equipment. You have $200. For how lo

IrinaVladis [17]

$25 + $35x = $200
$35x = $175 (subtracted the 25)
x = 5 hours (divided the 35)

So you could rent the boat for 5 hours.

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3 years ago

Which equation is equivalent to -3 x + y equals 5

Talja [164]

(x + -5)(x + -4) = 0
is the anwser

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3 years ago

3) 6 cm 5 cm I 7 cm 5 cm 6 cm

lord [1]

Answer:

Step-by-step explanation:

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3 years ago

Let X = the time between two successive arrivals at the drive-up window of a local bank. If X has an exponential distribution wi

LuckyWell [14K]

Answer:

a) E(X)=1

b) σ=1

c) P(X>1)=0.368

d) P(2<X<5)=0.128

Step-by-step explanation:

We have X: "the time between two successive arrivals at the drive-up window of a local bank", exponentially distributed with λ = 1.

a) We have to compute the expected time between two successive arrivals.

The expected value for X as it is exponentially distributed is:

$E(X)=\dfrac{1}{\lambda}=\dfrac{1}{1}=1$

b) We have to compute the standard deviation of X.

The standard deviation is calculated as:

$\sigma=\dfrac{1}{\lambda}=\dfrac{1}{1}=1$

c) The probability that X is larger than 1 (P(X>1))

We can express the probability as:

$P(X>t)=e^{-\lambda t}\\\\P(X>1)=e^{-\lambda\cdot 1}=e^{-1}=0.368$

d) The probability that X is between 2 and 5 (P(2<X<5))

$P(X>t)=e^{-\lambda t}\\\\\\P(25)\\\\P(2$

4 0

3 years ago

Please answer part b and part C!

max2010maxim [7]

Hey! Please do not use that link to download the answers. It’s fake and it’s a scam, they commented that on mine to so don’t do it

6 0

2 years ago

Read 2 more answers