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Ivenika [448]
3 years ago
10

What is the area of the given triangle ?

Mathematics
1 answer:
mylen [45]3 years ago
5 0

Answer:

12 units^2

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh

A = 1/2 ( 6 ) * 4

A = 1/2 (24)

    = 12 units^2

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What is the solution to the system of equations <br><br> 3x+2y=39<br> 5x-y=13
Vadim26 [7]

Hiya. I'm going to rewrite the second equation.

By subtracting 5x by both sides, I'll be able to have y by itself:

-y=-5x+13

I'm going to then divide both sides by -1 to get:

y=5x-13.


Then, I'm going to plug that equation into the first equation

3x+2(5x-13)=39

Factor:

3x+10x-26=39

Combine like terms:

13x=65

Divide both sides by 13 to get x by itself to get x=5


Plug this back into the equation of y=5x-13

y=5(5)-13 to get y=12

4 0
3 years ago
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The following pie chart represents how many absences the students of Washington Middle School had during the first quarter. What
Gekata [30.6K]

Answer:

68

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7 0
3 years ago
Danny's truck has a fuel tank with a capacity of 20 gallons of gas. The truck averages 17 miles per gallon of gas. The function
Fittoniya [83]

For this case we have the following function:

M (g) = 17g

Where,

g: number of gallons of gas

M (g): number of miles that Danny's truck travels

We know that the maximum capacity is 20 gallons of gas.

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M (20) = 17 (20)

M (20) = 340

Thus, the domain of the function is:

0 \leq g \leq 20

The range of the function is:

0 \leq M(g) \leq 340

Answer:

A domain and range that are reasonable for the function are:

D. D: 0 ≤ g ≤ 20

R: 0 ≤ M (g) ≤ 340

5 0
3 years ago
The residence of a city voted on whether to raise property taxes the ratio of yes votes to know votes was 5 to 6 if there was 58
Akimi4 [234]
5/6:x/5844

Cross multiply to get
29220=6x
x=4870

4870+5844=

10714 votes

Hope this helped :)
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2 years ago
The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.
Andrews [41]
<span>The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.
have four terms and 1 constant
</span>
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4 years ago
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