Equation a^2 + b^2 = c^2
c = longest side, unknown
The answer is D.
12^2 + 10^2 = c^2
By using the midpoint formula and the equation of the line, the equation of the line of symmetry is x = - 2.
<h3>How to derive the equation of the axis of symmetry </h3>
In this question we know the locations of two points with the same y-value, which means that the axis of symmetry is parallel to the y-axis and that both points are equidistant. Thus, the axis of symmetry passes through the midpoint of the line segment whose ends are those points.
First, calculate the coordinates of the midpoint by the midpoint formula:
M(x, y) = 0.5 · (- 7, 11) + 0.5 · (3, 11)
M(x, y) = (- 2, 11)
Second, look for the first coordinate of the midpoint and derive the equation of the line associated with the axis of symmetry:
x = - 2
By using the midpoint formula and the equation of the line, the equation of the line of symmetry is x = - 2.
To learn more on axes of symmetry: brainly.com/question/11957987
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Answer:
1. Slope-intercept form: 
Standard form: 
2. Slope-intercept form: 
Standard form: 
3. Slope-intercept form: 
Standard form: 
Step-by-step explanation:
Slope intercept form: 
where:
= y-coordinate
= slope
= x-coordinate
= y-intercept
Standard form: 
Slope-intercept form:
Standard form:
Slope-intercept form:
Standard form:
Slope-intercept form:
Standard form:
Answer:
p=1
Step-by-step explanation:
2/5 + p = 4/5 + 3/5p
Multiply each side by 5 to clear the fractions
5(2/5 + p) = 5(4/5 + 3/5p)
2 +5p = 4 + 3p
Subtract 3p from each side
2+5p-3p = 4+3p-3p
2+2p = 4
Subtract 2 from each side
2+2p -2 = 4-2
2p =2
Divide by 2
2p/2 = 2/2
p=1
What is the solution set of x2 + y2 = 26 and x − y = 6? A. {(5, -1), (-5, 1)} B. {(1, 5), (5, 1)} C. {(-1, 5), (1, -5)} D. {(5,
Rus_ich [418]
He two equations given are
x^2 + y^2 = 26
And
x - y = 6
x = y +6
Putting the value of x from the second equation to the first equation, we get
x^2 + y^2 = 26
(y + 6) ^2 + y^2 = 26
y^2 + 12y + 36 + y^2 = 26
2y^2 + 12y + 36 - 26 = 0
2y^2 + 12y + 10 = 0
y^2 + 6y + 5 = 0
y^2 + y + 5y + 5 = 0
y(y + 1) + 5 ( y + 1) = 0
(y + 1)(y + 5) = 0
Then
y + 1 = 0
y = -1
so x - y = 6
x + 1 = 6
x = 5
Or
y + 5 = 0
y = - 5
Again x = 1
So the solutions would be (-1, 5), (1 , -5). The correct option is option "C".
