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3 years ago

How many solutions does the following equation have? 3x + 6 = 3(x + 2)

1 answer:

8 0

3x+6=3(x+2)
3x+6=3x+6
minus 6 both sides
3x=3x
divide by 3
x=x

true

therefor all numbers work for x

there are infinite soltuions

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calculate the side lengths a and b to two decimal places angle a is 64 angle b is 85 and line ab is 9.3? PLEASE HELP ASAP

qaws [65]

∠C = 180° - (∠A + ∠B) = 180° - (64° + 85°) = 180° - 149° = 31°
$AC= \frac{9.3*sin(85)}{sin(31)} = \frac{9.3*0.9962}{0.515} =17,99 \\ \\ BC=\frac{9.3*sin(64)}{sin(31)} = \frac{9.3*0.8988}{0.515} =16,2$

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3 years ago

4. Solve for w:<br> -33 = 6 - 3w

gavmur [86]

Answer:

13 =w

Step-by-step explanation:

-33 = 6 - 3w

Subtract 6 from each side

-33-6 = 6 - 3w-6

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Divide each side by -3

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Step-by-step explanation:

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3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

$u=x$ $dv=e^(2x)\cdot{dx}$

$du=dx$ $v=2\cdot{e^(2x)}$

$\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du$

$\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx$

$\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C$

We can therefore determine that if x tends to 0 the limit is -1

$\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1$

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3 years ago