Answer:
10 pair of soccer shorts.
Step-by-step explanation:
Let the unknown be x.
Translating the word problem into an algebraic equation, we have;
2/5 yard = 1 pair of short
4 yard = x pair of short
Cross-multiplying, we have;
2x/5 = 4
Multiplying both sides by 5, we have;
2x = 20
x = 20/2
x = 10 pair of soccer shorts.
1) Answer: The part of the quadratic formula tells us whether the quadratic equation can be solved by factoring is b^2-4ac
2) 4x^2+6x+2=0
ax^2+bx+c=0; a=4, b=6, c=2
b^2-4ac=(6)^2-4(4)(2)=36-32
b^2-4ac=4
Answer: b^2-4ac=4
In this problem you will need to use the Pythagorean theorem (c^2=a^2+b^2).
The a and b represents the two edges, while c is the diagonal side and it is called the hypotenuse. Since you already know what the hypotenuse is and what one of the sides already are you just have to use the problem: c^2-a^2=b^2. Then if you plug the data you already have into the problem you will get 10^2-6^2=b^2. That then equals 100-36=b^2. Then you subtract and get b^2=64. Then you square root both sides and you get the answer b=8.
